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Tanzania [10]
3 years ago
7

Which function is graphed below ​

Mathematics
2 answers:
Marianna [84]3 years ago
5 0

Answer:

y = tan(x) - 2

Step-by-step explanation:

Veronika [31]3 years ago
3 0

Answer:

y=tan(x)-2

Step-by-step explanation:

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The perimeter of a rectangle is 40 m. The length is 4 m more than three times the width. Find the length and the width of the re
galina1969 [7]

Answer:

Width = 4 m, Length = 16 m

Step-by-step explanation:

Perimeter = 40

Width = x

Length = 3x + 4

x + x + 3x + 3x + 4 + 4 = 8x + 8

40 - 8 = 32

32/8 = x

x = 4

Width = 4

Length = 16

Please mark as Brainliest, thank you!

8 0
3 years ago
Who is good with math like trig.??
Mnenie [13.5K]
I am good with all math from alg-calc
4 0
4 years ago
Rewrite in simplest radical form! Show your work.
vazorg [7]

x^{\frac{1}{\frac{-3}{6} }}

First, let's deal with the fraction in the denominator of the exponent. Multiply the top and bottom of the exponent by 6.

x^{\frac{6}{-3} }

Now that the fraction in the denominator is taken care of, we can reduce the denominator.

x^{-2}. Some professors might accept this as simplest form, but others might ask you to get rid of the negative.

x^{-2} = \frac{1}{x^{2} }

7 0
3 years ago
Read 2 more answers
Suppose you toss a fair coin 10 times, let X denote the number of heads. (a) What is the probability that X=5? (b) What is the p
zubka84 [21]

Answer:  The required answers are

(a) 0.25,    (b) 0.62,    (c) 6.

Step-by-step explanation:  Given that we toss a fair coin 10 times and X denote the number of heads.

We are to find

(a) the probability that X=5

(b) the probability that X greater or equal than 5

(c) the minimum value of a such that P(X ≤ a) > 0.8.

We know that the probability of getting r heads out of n tosses in a toss of coin is given by the formula of binomial distribution as follows :

P(X=r)=^nC_r\left(\dfrac{1}{2}\right)^r\left(\dfrac{1}{2}\right)^{n-r}.

(a) The probability of getting 5 heads is given by

P(X=5)\\\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}\\\\\\=\dfrac{10!}{5!(10-5)!}\dfrac{1}{2^{10}}\\\\\\=0.24609\\\\\sim0.25.

(b) The probability of getting 5 or more than 5 heads is

P(X\geq 5)\\\\=P(X=5)+P(X=6)+P(X=7)+P(X=8)+P(X=9)+P(X=10)\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}+^{10}C_6\left(\dfrac{1}{2}\right)^6\left(\dfrac{1}{2}\right)^{10-6}+^{10}C_7\left(\dfrac{1}{2}\right)^7\left(\dfrac{1}{2}\right)^{10-7}+^{10}C_8\left(\dfrac{1}{2}\right)^8\left(\dfrac{1}{2}\right)^{10-8}+^{10}C_9\left(\dfrac{1}{2}\right)^9\left(\dfrac{1}{2}\right)^{10-9}+^{10}C_{10}\left(\dfrac{1}{2}\right)^{10}\left(\dfrac{1}{2}\right)^{10-10}\\\\\\=0.24609+0.20507+0.11718+0.04394+0.0097+0.00097\\\\=0.62295\\\\\sim 0.62.

(c) Proceeding as in parts (a) and (b), we see that

if a = 10, then

P(X\leq 0)=0.00097,\\\\P(X\leq 1)=0.01067,\\\\P(X\leq 2)=0.05461,\\\\P(X\leq 3)=0.17179,\\\\P(X\leq 4)=0.37686,\\\\P(X\leq 5)=0.62295,\\\\P(X\leq 6)=0.82802.

Therefore, the minimum value of a is 6.

Hence, all the questions are answered.

3 0
4 years ago
Which ordered pairs are solutions to the inequality −2x+y≥−4 ?
GalinKa [24]
The answer would be A
3 0
3 years ago
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