Answer:
the relation between them are
n(U) = n(X U Y) + n(xūy).
Answer:
The score that separates the lower 5% of the class from the rest of the class is 55.6.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:

Find the score that separates the lower 5% of the class from the rest of the class.
This score is the 5th percentile, which is X when Z has a pvalue of 0.05. So it is X when Z = -1.645.


The score that separates the lower 5% of the class from the rest of the class is 55.6.
Is it D? if not i’m so sorry
<span>December = $57
</span><span>In December, the price was $57, which was $29 less than the price in November then November price was: $57 + $29 = $86
</span><span>In November, the price of a GizmoPhone was double the price in March. so March: $86 x 2 = $172
answer: the price </span>of a GizmoPhone in March was $172