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zlopas [31]
3 years ago
10

Find the ordered pairs for the x- and y-intercepts of the equation 3x - 2y =18

Mathematics
1 answer:
Len [333]3 years ago
5 0
X-int:let y=0
3x-2(0)=18
3x=18
divide both sides by 3
therefore x=6
y-int:let x=0
3(0)-2y=18
-2y=18
we divide both side by -2
therefore y=-9
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Find the approximate value of each trigonometric function.
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Answer:

<u>Given</u>

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  • θ is in the III quadrant

We know in the III quadrant both sine and cosine are negative.

<u>Use the following identities to get values of sinθ and cos θ</u>

  • sinθ = - tanθ/√(1 +tan²θ)
  • cosθ = - 1/√(1 +tan²θ)

<u>Substitute the value of tanθ and find sine and cosine:</u>

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  • cosθ = - 1/√(1 + 3.454²) = - 0.278

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lesantik [10]
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Phantasy [73]
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What’s the question?
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