Answer:
Cubic polynomial has zeros at x=−1x=−1 and 22, is tangent to x−x−axis at x=−1x=−1, and passes through the point (0,−6)(0,−6).
So cubic polynomial has double zero at x=−1x=−1, and single zero at x=2x=2
f(x)=a(x+1)2(x−2)f(x)=a(x+1)2(x−2)
f(0)=−6f(0)=−6
a(1)(−2)=−6a(1)(−2)=−6
a=3a=3
f(x)=3(x+1)2(x−2)f(x)=3(x+1)2(x−2)
f(x)=3x3−9x−6
Answer:
<h2>
<em><u>brainleist plz</u></em></h2>
Step-by-step explanation:
first lets do the x^2 part
1/2^2 = 1/4
now 1/4 ^3
equals = <em><u>1/64</u></em>
Answer:
Step-by-step explanation:
The general equation of a circle is , x² + y² + 2gx + 2fy + c = 0
Substituting the three points we get the following equations,
2g +14f +c=-50
14g - 2f + c =-50
16g +12f + c = -100
Solving these equations we get,
g =-4, f = -3, c = 0
Hence general equation of circle is,
x² + y² - 8x - 6y = 0
The first step in solving quadratic equations by finding square roots is; C:square root both sides to isolate x
<h3>How to solve quadratic equations?</h3>
To answer this question, we will take an example of a quadratic equation that we need to find the square root as;
x² = 36
Now, to get the roots which are the values of x, we will first have to take the square root of both sides to Isolate x. Thus;
√x² = √36
x = ±6
Read more about quadratic equations at; brainly.com/question/1214333
#SPJ1
