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boyakko [2]
3 years ago
11

Let S = {4, 6, 8} and T = {3, 5, 7}. Use the set roster notation to write each of the following sets, and indicate the number of

elements that are in each set. (Enter your answers as a comma-separated list of ordered pairs.) (a) S ✕ T S ✕ T = Number of elements in S ✕ T = (b) T ✕ S T ✕ S = Number of elements in T ✕ S = (c) S ✕ S S ✕ S = Number of elements in S ✕ S = (d) T ✕ T T ✕ T = Number of elements in T ✕ T =
Mathematics
1 answer:
allochka39001 [22]3 years ago
5 0

Answer:

See explanation

Step-by-step explanation:

<u>Definition:</u> S\times T=\{(s,t)|s\in S,\ t\in T\}

<u>Given:</u> S=\{4,6,8\},\ T=\{3,5,7\}

1. Find S\times T:

S\times T=\{(4,3),(4,5),(4,7),(6,3),(6,5),(6,7),(8,3),(8,5),(8,7)\}

There are 9 elements.

2. Find T\times S:

T\times S=\{(3,4),(3,6),(3,8),(5,4),(5,6),(5,8),(7,4),(7,6),(7,8)\}

There are 9 elements.

3. Find S\times S:

S\times S=\{(4,4),(4,6),(4,8),(6,4),(6,6),(6,8),(8,4),(8,6),(8,8)\}

There are 9 elements.

4. Find T\times T:

T\times T=\{(3,3),(3,5),(3,7),(5,3),(5,5),(5,7),(7,3),(7,5),(7,7)\}

There are 9 elements.

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Arrange the steps in the correct order to solve the equation 3 (2^2t-5 )- 4=10
liberstina [14]
The equation to be solved is: 3 [ 2 ^ (2t - 5) ] - 4 = 10

The steps are:

1) transpose - 4=> 3 [ 2^ (2t - 5) ] = 10 + 4

2) Combine like terms => 3 [2^ (2t - 5) ] = 14

3) Divide both terms by 3 => 2^ (2t - 5) = 14 / 3

4) Take logarithms of both sides => (2t - 5) log (2) = log (14/3)

5) Divide both sides by log (2) =>

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2t - 5 = -------------------
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6) transpose - 5+>

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8 0
3 years ago
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The sum of two consecutive multiples of 5 is 55.what are the multiples ​
wariber [46]

Answer:

25 and 30

Step-by-step explanation:

Let the smaller consecutive multiples of 5 be x. Therefore, other consecutive multiples will be x + 5.

Now as per statement the sum of two consecutive multiples of 5 is 55. To find the multiples. Thus

x + x + 5 = 55

2x + 5 = 55

2x = 55 - 5

2x = 50

x = 50/2

x = 25

This the smaller consecutive multiples of 5 is 25, the other consecutuve multiple is x+ 5, 25 + 5 = 30.

The consecutive multiple numbers of 5 are 25 and 30

Answer the two consecutive multiples of 5 are 25 and 30

5 0
3 years ago
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