Question

What is the solution to the system of equations?

Answer 1

ANSWER

C) (6,-8)

EXPLANATION

The equations are:

$y = \frac{1}{3}x - 10$

and

$2x+y=4$

We substitute the first equation into the second equation to get:

$2x + \frac{1}{3}x - 10 = 4$

We multiply through by 3 to get:

$6x + x - 30= 12$

Group similar terms,

$6x + x = 30 + 12$

$7x = 42$

Divide both sides by 7 to get,

$x = \frac{42}{7} = 6$

Put this value of x into the first equation to get;

$y = \frac{1}{3} (6) - 10$

$y = 2 - 10 = - 8$