Write an equation in slope -intercept form for the line with slope -2/3 and y-intercept 5. Then graph

At the city museum, child admission is $5.70 and adult admission is $9.50. on Friday, 155 tickets were sold for a total sales of

Alja [10]

i love brainless tttree

8 0

3 years ago

Read 2 more answers

Solve this identifying holes, vertical asymptotes, and horizontal asymptotes for

USPshnik [31]

$x^2+7x+12=x^2+4x+3x+12=x(x+4)+3(x+4)=(x+4)(x+3)\\\\-x^2-3x+4=-(x^2+3x-4)=-(x^2+4x-x-4)\\\\=-[x(x+4)-1(x+4)]=-(x+4)(x-1)\\\\f(x)=\dfrac{x^2+7x+12}{-x^2-3x+4}=\dfrac{(x+4)(x+3)}{-(x+4)(x-1)}\\\\\text{Vertical asymptotes:}\\\\(x+4)(x-1)=0\iff x+4=0\ \vee\ x-1=0\\\\\boxed{x=-4\ and\ x=1}\\\\\text{Horizontal asymptotes:}$

$\lim\limits_{x\to\pm\infty}\dfrac{x^2+7x+12}{-x^2-3x+4}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(1+\dfrac{7}{x}+\dfrac{12}{x^2}\right)}{x^2\left(-1-\dfrac{3}{x}+\dfrac{4}{x^2}\right)}=\dfrac{1}{-1}=-1\\\\\boxed{y=-1}$

6 0

4 years ago

an electronics company is designing a watch with a face that is in the shape of a hexagon and two congruent trapezoids attached.

nalin [4]

The total area of the face of the watch to the nearest tenth of a square centimemter is 9.0 cm²

Since an electronics company is designing a watch with a face that is in the shape of a hexagon and two congruent trapezoids attached. The heights of the trapezoids and the apothem of the hexagon measure 2 centimeters each, and the length of the shorter base of each trapezoid is 1.5 centimeters, the radii of the hexagon, and the base of the trapezoid form a triangle of

height, h = apothem of the hexagon = 2 cm and
base, b = length of shorter base of trapezoid.

<h3>Area of the triangle</h3>

So, the area of this triangle is A = 1/2bh

= 1/2 × 1. 5 cm × 2 cm

= 1.5 cm × 1 cm

= 1.5 cm²

<h3>Area of the hexagon</h3>

Since there are 6 of such triangles in the hexagon, the area of the hexagon, A' = 6A

= 6 × 1.5 cm²

= 9.0 cm²

So, the total area of the face of the watch to the nearest tenth of a square centimemter is 9.0 cm²

Learn more about area of a hexagon here:

brainly.com/question/369332

5 0

2 years ago

What is the volume of a rectangular prism that is 16 meters by 25 meters by 37 meters?

ElenaW [278]

Answer:

14,800

Step-by-step explanation:

To find the volume of an object, simply multiply its hight, length, and width together.

16*25*37

16*25=400

400*37=14,800

The rectangular prism has a volume of 14,800.

Hope this helps!

4 0

3 years ago

A rectangle is 20 meters long and 20 meters wide. If the length is increased by 10% and the width is decreased by 10%, what is t

Solnce55 [7]

Consider that the initial length and width of the rectangle are given as,

$\begin{gathered} l=20 \\ b=20 \end{gathered}$

After the length is increased by 10%, the new length (L) of the rectangle is calculated as,

$\begin{gathered} L=(1+\frac{10}{100})\cdot l \\ L=(\frac{110}{100})\cdot20 \\ L=22 \end{gathered}$

After the width is decreased by 10%, the new width (B) of the rectangle is calculated as,

$\begin{gathered} B=(1-\frac{10}{100})\cdot b \\ B=(\frac{90}{100})\cdot20 \\ B=18 \end{gathered}$

Then the area (A) of the new rectangle is calculated as,

$\begin{gathered} A=L\times B \\ A=22\times18 \\ A=396 \end{gathered}$

Thus, the new area of the rectangle is 396 square meters.

7 0

1 year ago