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3 years ago

What is a factors for -12

Mathematics

1 answer:

Rzqust [24]3 years ago

4 0

Answer:

4-16= -12

16-28= -12

Step-by-step explanation:

frognj;ghgrue;jnvougheruo'gln

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dsp73

Answer:

That big "E" word means the same lengths so they are all 14" long

Step-by-step explanation:

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3 years ago

1/2a + 5(3a + 3/2 Please help

Morgarella [4.7K]

Answer is below in picture

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3 years ago

Can you help me please!!!! please!!!! :)

Anastasy [175]

Answer:

Qn.1

{4,5,6,7,8,9,12,15,16}is ans of 1

{8,9}is ans of 2

{4,5,6,7,8,9,18,20}is ans of 3

{}Is the ans of 4

{8,9,12,15,16,18,20}is ans of 5

{}is ans of 6

{4,5,6,7,8,9,12,15,16,18,20} is ans of 7

{8,9,12,15,16} is ans of 8

Qn.2

{0,12}is ans of 9

{0,2,10,12}is ans of 10

{0,4,6,8,12}is ans of 11

{2,4,6,8,10}Is ans of 12

{}is ans of 13

{0,12}is ans 14

{0,12} is ans 15

{0,2,10,12} is ans of 16

{0,12} is ans of 17

{0,12} is ans of 18

{2,10} is ans of 19

{4,6,8} is ans of 20

I haven't made the symbol of union and intersection because i don't how to make.

it may help you at your work

4 0

3 years ago

Solve the Anti derivative.

Alex Ar [27]

Answer:

$\displaystyle \int {\frac{1}{9x^2+4}} \, dx = \frac{1}{6}arctan(\frac{3x}{2}) + C$

General Formulas and Concepts:

Algebra I

Factoring

Calculus

Antiderivatives - integrals/Integration

Integration Constant C

U-Substitution

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Trig Integration: $\displaystyle \int {\frac{du}{a^2 + u^2}} = \frac{1}{a}arctan(\frac{u}{a}) + C$

Step-by-step explanation:

Step 1: Define

$\displaystyle \int {\frac{1}{9x^2 + 4}} \, dx$

Step 2: Integrate Pt. 1

[Integral] Factor fraction denominator: $\displaystyle \int {\frac{1}{9(x^2 + \frac{4}{9})}} \, dx$
[Integral] Integration Property - Multiplied Constant: $\displaystyle \frac{1}{9} \int {\frac{1}{x^2 + \frac{4}{9}}} \, dx$

Step 3: Identify Variables

Set up u-substitution for the arctan trig integration.

$\displaystyle u = x \\ a = \frac{2}{3} \\ du = dx$

Step 4: Integrate Pt. 2

[Integral] Substitute u-du: $\displaystyle \frac{1}{9} \int {\frac{1}{u^2 + (\frac{2}{3})^2} \, du$
[Integral] Trig Integration: $\displaystyle \frac{1}{9}[\frac{1}{\frac{2}{3}}arctan(\frac{u}{\frac{2}{3}})] + C$
[Integral] Simplify: $\displaystyle \frac{1}{9}[\frac{3}{2}arctan(\frac{3u}{2})] + C$
[integral] Multiply: $\displaystyle \frac{1}{6}arctan(\frac{3u}{2}) + C$
[Integral] Back-Substitute: $\displaystyle \frac{1}{6}arctan(\frac{3x}{2}) + C$