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umka2103 [35]
4 years ago
11

Geometry-10th Grade-Paralellograms can you solve for x?(25 points)

Mathematics
1 answer:
Anvisha [2.4K]4 years ago
6 0

Answer:

x = 5 1/3

Step-by-step explanation:

AD // BK

∠DAk ≅ ∠BKA  ≅ ∠KAB     ∴ AB = 10 = BK = BC + CK = 6 + CK

∴ CK = 4

ΔKFC similar to ΔAFD   (AAA)

KC / KD = KF / (FE + EA)        4/6 = 2/3 = x / (3 + y)

3x = 6 + 2y --- (1)

ΔAED similar to ΔKEB   (AAA)

AE / EK = AD / BK        y / (3 + x) = 6 / 10 = 3 / 5

3x + 9 = 5y          3x = 5y - 9-------- (2)

6 + 2y = 5y - 9

3y = 15        y = 5

x = (5 x 5 - 9) /3 = 16/3 = 5 1/3

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Answer:

Step-by-step explanation:

We have:

2.4, 11, 4, 2, 1, 5.

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1, 2, 2.4, 4, 5, 11.

8 0
3 years ago
really need help on these two questions for geometry, please actually answer it instead of just grabbing points and leaving :')
zhuklara [117]

Answer:

Step-by-step explanation:

E and F are horizontally aligned, so the slope of  EF is 0 and its length is 16-10 = 6.

G and H are horizontally aligned, so the slope of  GH is 0 and its length is 16-10 = 6.

F and G are vertically aligned, so FG is vertical and its length is 10-4 = 6.

E and HG are vertically aligned, so EH is vertical and its length is 10-4 = 6.

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8 0
3 years ago
The ratio of laptop to desktop computers at a middle school. Is 8 to 6. If there are 462 desktop computers, how many computers i
Aleksandr-060686 [28]

Answer:

1078

Explanation:

For this you can use a proportion to solve. So first we set up the proportion as  laptop over desktop is equal to "<em>l</em>" over total desktop computers. Let <em>l</em> be the total amount of laptops which is what we must first solve for.

\frac{8}{6}=\frac{l}{462} \\

Then we cross multiply.

6l=3696\\

Now we can solve it as a regular algebra problem,

\frac{6}{6}l = \frac{3696}{6}\\  l=616

Now that we know how many laptop computers there are we can find the total number of computers in the school. We simply add the total number of desktop computers to the total number of laptop computers.

462+616=1078

And that is the answer. 1078.

7 0
3 years ago
Which of the following equations have no solutions?
Ivahew [28]

Answer:

A, C, D

Step-by-step explanation:

Solve all equations:

A. 33x-25=33x+25

33x-33x=25+25\\ \\0=50

This is incorrect equality, so the equation has no solutions.

B. 33x+25=33x+25

33x-33x=25-25\\ \\0=0

This is correct equality, so the equation has infinitely many solutions.

C. 33x-33=33x+25

33x-33x=33+25\\ \\0=58

This is incorrect equality, so the equation has no solutions.

D. 33x+33=33x+25

33x-33x=25-33\\ \\0=-8

This is incorrect equality, so the equation has no solutions.

7 0
4 years ago
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hram777 [196]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
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