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3 years ago

Which quadratic regression equation best fits the data set?

Mathematics

2 answers:

BaLLatris [955]3 years ago

8 0

Answer:

y = 1.87x² - 5.16x + 10.54

Step-by-step explanation:

I have attached the scatterplot of the data with each graph drawn on it.

We can see that the one that fits best is the first equation,

y = 1.87x² - 5.16x + 10.54.

nata0808 [166]3 years ago

6 0

Answer: $y = 1.87x^2 -5.16 x + 10.54$

Step-by-step explanation:

Since the general quadratic equation is,

$y = ax^2 + bx+c$

Here the given table is,

x 1 2 3 4 5 6 7

y 5.9 8.9 13.4 20.1 30.1 45.1 67.7

By the graphing calculator,

a = 1.87024 ≈ 1.87

b= -5.15833 ≈ -5.15

c = 10.5429 ≈ 10.54

By putting the values of a, b and c,

The required quadratic equation is,

$1.87 x^2 -5.15x + 10.54$

⇒ First Option is correct.

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Please! Need help! Please answer 6 through 10! Brainliest! As a reward!

True [87]

Answer:

6=72 cm; 7=15 cm; 8=30 in; 9)56.5 degrees; 10)40 in

Step-by-step explanation:

6) The height of the triangle is 12 cm. The base is around 10 cm. Triangles are 1/2(b)h, so:

1/2(10)=5

5*12=60 cm

72 is closest to this.

7) Volume is l*w*h, so:

2.5*1.5=3.75

3.75*4=15 cm

8) Again, the height is 5 and the base is 12. 1/2(b)h means:

1/2(12)=6

6*5=30 in

9) All triangles have 180 degrees. So first, add the degrees you know:

33.5+90=123.5

Now, subtract that from 180:

180-123.5=56.5

10) Trapezoids can be found by multiplying the height by the smaller base, so:

6*8=40 in

Hope this helped!

4 0

2 years ago

Mr. Harrow has eight boys and six girls in his Honors Pre-calculus class. If he randomly chooses two students, one at a time, wh

Sergeu [11.5K]

Answer: 15/91 which is choice B

=================================================================

There are two methods to find this answer.

Method 1) We have 6 girls and 8+6 = 14 students. The probability of picking a girl is 6/14 = 3/7. After the first girl is chosen, we have 5 girls left out of 14-1 = 13 students overall. The probability of picking another girl (assuming the first selection was a girl) is 5/13. Multiply these probabilities: (3/7)*(5/13) = (3*5)/(7*13) = 15/91

--------------------

Method 2) We can use the nCr combination formula. Order does not matter.

We have nCr = 6 C 2 = 15 ways to pick 2 girls. See the attached image below for the steps (figure 1)

Out of nCr = 14 C 2 = 91 ways to pick 2 students. See the attached image below for the steps (figure 2)

So that's another way to get the answer 15/91.