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dybincka [34]
3 years ago
11

Jana and her friend bought 4 hamburgers, 3 orders of fries, and 2 milk shakes for $3 each. They paid for the food with $20. Whic

h part of the equation represents the total cost of their items? Justify your answer.
c = $20 - (4h + 3f + 6)

A) $20; They paid $20 for the food.
B) (4h + 3f); Find the total cost by adding the price of 4 hamburgers to the price of 3 fries
C) 4h + 3f + 6; Find the total cost by adding the price of 4 hamburgers to the price of 3 fries to the price of 2 milkshakes.
D) c = 20 - (4h + 3f + 6); Find the total cost by subtracting the price of 4 hamburgers to the price of 3 fries to the price of 2 milkshakes.
Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
5 0

For this case we have the following variables:

h: Cost of each hamburger bought by Jana and her friend

f: Cost of each order of potato chips bought by Jana and her friend

b: Cost of each milkshake

If you bought 4 hamburgers, 3 orders of potatoes and 2 milkshakes, you have a cost of:

Cost = 4h + 3f + 2b

It is known that each shake costs $ 3, sob =3$

Substituting we have:

Cost = 4h + 3f + 2 * 3

Cost = 4h + 3f + 6

Thus, the total cost is given by:

Cost = 4h + 3f + 6

Answer:

Cost = 4h + 3f + 6

Option C


devlian [24]3 years ago
3 0
I believe the correct answer is C
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V125BC [204]
U can do this 2 ways....
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3 0
3 years ago
Beau's recipe fro granola bars calls for 3 1/2 cups of oatmeal. He only has 1/6 scoop. How many scoops of oatmeal will he need t
natulia [17]

\boxed{21} scoops of oatmeal will he need to complete the recipe.

Further explanation:

Given:

Beau's recipe from granola bars calls for 3\dfrac{1}{2} cups of oatmeal.

He only is \dfrac{1}{6} scoop.

Explanation:

The cups of oatmeal called for the recipe is 3\dfrac{1}{2}.

Solve the improper fraction 3\dfrac{1}{2}.

\begin{aligned}{\text{Fraction}}&=\frac{{2 \times 3 + 1}}{2}\\&=\frac{{6 + 1}}{2}\\&=\frac{7}{2}\\\end{aligned}

The Beau has \dfrac{1}{6}{\text{ scoop}}.

The number of scoops required to complete the recipe can be obtained as follows,

\begin{aligned}N&=\frac{{{\text{total cups of oatmeal}}}}{{{\text{the fraction of scoop Beau has}}}}\\&=\frac{{\frac{7}{2}}}{{\frac{1}{6}}}\\&= \frac{7}{2} \times6\\&=\frac{{42}}{2}\\&= 21\\\end{aligned}

Number of scoops required to complete the oatmeal is 21{\text{ scoops}}.

Therefore, \boxed{21} scoops of oatmeal will he need to complete the recipe.

Learn more:

1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.

2. Learn more about equation of circle brainly.com/question/1506955.

3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: Middle School

Subject: Mathematics

Chapter: Fractions

Keywords: fraction, Beau’s recipe, granola bars, calls, 3 1/2 cups of oatmeal, scoops, recipe, ratio, 1/6 scoop, complete the recipe.

5 0
3 years ago
ANSWER ASAP PLEASEEEEEE
expeople1 [14]

Answer:

the answer is A

Step-by-step explanation:

....................

8 0
2 years ago
Read 2 more answers
In ∆XYZ, m∠X = 152, y = 15, and z = 19. Find side x and the measure of angle Y to the nearest tenth
solong [7]

The measure of the side x is approximately 33 and the measure of angle Y is approximately 12.321°.

<h3>How to find a missing angle in a triangle by law of sine and law of cosine</h3>

In this problem we must apply the law of cosine and the law of sine to determine the angle Y:

<h3>Law of cosine</h3>

x = \sqrt{y^{2}+z^{2}-2\cdot y\cdot z\cdot \cos X}

x = \sqrt{15^{2}+19^{2}-2\cdot (15)\cdot (19)\cdot \cos 152^{\circ}}

x \approx 33

<h3>Law of sine</h3>

\frac{\sin Y}{y} = \frac{\sin X}{x}

Y = \sin^{-1}\left(\frac{y}{x}\cdot \sin X \right)

Y = \sin^{-1}\left(\frac{15}{33}\cdot \sin 152^{\circ} \right)

Y \approx 12.321^{\circ}

The measure of the side x is approximately 33 and the measure of angle Y is approximately 12.321°. \blacksquare

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7 0
2 years ago
Please let me know the correct answer.
NNADVOKAT [17]

Set h to 640 and solve for t:

640 = -490t^2 + 1120t

Subtract 640 from both sides:

-490t^2 + 1120t - 640 = 0

The formula to solve a quadratic equation is:

x = -b -/+ sqrtroot (b^2-4ac)/(2a) where a = -490, b = 1120 and c = -640

Solve:

x = -1120 -/+ sqrtroot (1120^2-4(-490)(-640) )/ 2(-490)

x = 8/7 = 1.1428 = 1.14

Time was 1.14 seconds

4 0
3 years ago
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