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dybincka [34]
2 years ago
11

Jana and her friend bought 4 hamburgers, 3 orders of fries, and 2 milk shakes for $3 each. They paid for the food with $20. Whic

h part of the equation represents the total cost of their items? Justify your answer.
c = $20 - (4h + 3f + 6)

A) $20; They paid $20 for the food.
B) (4h + 3f); Find the total cost by adding the price of 4 hamburgers to the price of 3 fries
C) 4h + 3f + 6; Find the total cost by adding the price of 4 hamburgers to the price of 3 fries to the price of 2 milkshakes.
D) c = 20 - (4h + 3f + 6); Find the total cost by subtracting the price of 4 hamburgers to the price of 3 fries to the price of 2 milkshakes.
Mathematics
2 answers:
Svetradugi [14.3K]2 years ago
5 0

For this case we have the following variables:

h: Cost of each hamburger bought by Jana and her friend

f: Cost of each order of potato chips bought by Jana and her friend

b: Cost of each milkshake

If you bought 4 hamburgers, 3 orders of potatoes and 2 milkshakes, you have a cost of:

Cost = 4h + 3f + 2b

It is known that each shake costs $ 3, sob =3$

Substituting we have:

Cost = 4h + 3f + 2 * 3

Cost = 4h + 3f + 6

Thus, the total cost is given by:

Cost = 4h + 3f + 6

Answer:

Cost = 4h + 3f + 6

Option C


devlian [24]2 years ago
3 0
I believe the correct answer is C
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Bart company charges a lower rate. It is lower by rate $ 0.5 per hour

<h3><u>Solution:</u></h3>

Given that Ace bike rentals rents bikes for $28 per day. Renters can keep the bike for 8 hours

Also given that Bart's bikes rents bikes for $30 per day. Renters can keep the bike for 10 hours

To find: company that charges lower rate

Let us find the hourly rate of Ace and Bart

\text {hourly rate }=\frac{\text { Rental price }}{\text { total time in a day }}

<em><u>Hourly rate of Ace company:</u></em>

Rental price = $28

total time in a day 8 hours

\text {hourly rate }=\frac{28}{8}=3.5

So the hourly rate of Ace company is $ 3.5 per hour

<em><u>Hourly rate of Bart company:</u></em>

Rental price = $ 30

total time in a day 10 hours

\text {hourly rate }=\frac{30}{10}=3

So the hourly rate of Bart company is $ 3 per hour

<em><u>Comparing hourly rate of both companies</u></em>

Ace company is $ 3.5 per hour

Bart company is $ 3 per hour

Bart company < Ace company

3 < 3.5

Thus bart company charges a lower rate

<h3><em><u>How much lower?</u></em></h3>

hourly rate of Ace company - hourly rate of Bart company = 3.5 - 3 = 0.5

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6 0
3 years ago
In the triangle shown we can find the angle θ as follows calculator
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Given a right triangle with hypothenus of measure 34, the side opposite the angle θ of measure 30, and the side adjacent the angle theta of measure 16.

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3 years ago
One of the earliest applications of the Poisson distribution was in analyzing incoming calls to a telephone switchboard. Analyst
grandymaker [24]

Answer:

(a) P (X = 0) = 0.0498.

(b) P (X > 5) = 0.084.

(c) P (X = 3) = 0.09.

(d) P (X ≤ 1) = 0.5578

Step-by-step explanation:

Let <em>X</em> = number of telephone calls.

The average number of calls per minute is, <em>λ</em> = 3.0.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 3.0.

The probability mass function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,3...

(a)

Compute the probability of <em>X</em> = 0 as follows:

P(X=0)=\frac{e^{-3}3^{0}}{0!}=\frac{0.0498\times1}{1}=0.0498

Thus, the  probability that there will be no calls during a one-minute interval is 0.0498.

(b)

If the operator is unable to handle the calls in any given minute, then this implies that the operator receives more than 5 calls in a minute.

Compute the probability of <em>X</em> > 5  as follows:

P (X > 5) = 1 - P (X ≤ 5)

              =1-\sum\limits^{5}_{x=0} { \frac{e^{-3}3^{x}}{x!}} \,\\=1-(0.0498+0.1494+0.2240+0.2240+0.1680+0.1008)\\=1-0.9160\\=0.084

Thus, the probability that the operator will be unable to handle the calls in any one-minute period is 0.084.

(c)

The average number of calls in two minutes is, 2 × 3 = 6.

Compute the value of <em>X</em> = 3 as follows:

<em> </em>P(X=3)=\frac{e^{-6}6^{3}}{3!}=\frac{0.0025\times216}{6}=0.09<em />

Thus, the probability that exactly three calls will arrive in a two-minute interval is 0.09.

(d)

The average number of calls in 30 seconds is, 3 ÷ 2 = 1.5.

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P (X ≤ 1 ) = P (X = 0) + P (X = 1)

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Thus, the probability that one or fewer calls will arrive in a 30-second interval is 0.5578.

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Irina18 [472]
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tamaranim1 [39]
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