The half life of a drug in the bloodstream is 18 hours. What fraction of the original drug dose remains in 36 hours? in 72 hours
1 answer:
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Answer:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Step-by-step explanation:
For this case first we need to create the sample of size 20 for the following distribution:
And we can use the following code: rnorm(20,50,6) and we got this output:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
First write the inequality: 15
4.75x +3.50
Then to solve, first subtract 3.50 from both sides to get:
11.504.75x
Then divide by 4.75 to get 2.42, and since you can't buy .42 of a bag of fruit, you round down. So your final answer would be 2 bags of fruit.
Then to solve, first subtract 3.50 from both sides to get:
11.50
Then divide by 4.75 to get 2.42, and since you can't buy .42 of a bag of fruit, you round down. So your final answer would be 2 bags of fruit.
You need to find the area of the hexagon, and the area of the triangle.
The formula for the area of a triangle is
I hope this helps you a little.