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kvv77 [185]
2 years ago
5

The half life of a drug in the bloodstream is 18 hours. What fraction of the original drug dose remains in 36 hours? in 72 hours

?
Mathematics
1 answer:
xxTIMURxx [149]2 years ago
5 0

Answer:

1/4 in 36 hours

1/8 in 72 hours

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EASY 10 POINTS AND BRAINLEIST
Semmy [17]

Answer:

8t\leq 100

Step-by-step explanation:

T-shirts-<em>t</em>

<em />8t\leq 100<em />

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2 years ago
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In May you used 900 ​kilowatt-hours of energy for electricity.
Sloan [31]

Answer:

a) "The total electrical energy use was 3,240,000,000 joules."

b) "The average power use is 1210 watts."

c)

<u>Part 1:</u> "To generate the electricity you​ used, 810 L is needed."

<u>Part 2:</u> "To generate the electricity you​ used, 214.00 gal is needed."

Step-by-step explanation:

a)

1 kilowatt-hours = 3.6x10^6 joules

Converting 900 kilowatt-hours to joules, we have:

900*(3.6*10^6)=3.24*10^9 joules, or

Total Electrical Energy use = 3,240,000,000 joules

"The total electrical energy use was 3,240,000,000 joules."

b)

The month of May has 31 days and 1 day  is 24 hours. So May has:

31*24=744 hours

Now, we divide 900 kW-hr by the number of hours in the month (744 hrs) to get average power use:

\frac{900}{744}=1.21 kW. Since 1000 Watts = 1 kW, we multiply this by 1000 to get the answer in Watts:

1.21 * 1000 = 1210 Watts

"The average power use is 1210 watts."

c)

<u>Part 1:</u>

The conversion efficiency of most generating stations is 33%. So we need to multiply the total electrical energy use (in joules) by a factor of 3 to get the amount of joules required. So:

(3.24 * 10^9)*3 = 9.72 * 10^9 joules

We divide this by 12 million joules to get the number of liters:

\frac{9.72*10^9}{12*10^6}=810

So, 810 liters is needed

"To generate the electricity you​ used, 810 L is needed."

<u>Part 2:</u>

We know that 0.2642 gallons is equal to 1 liters. To get the number of gallons needed, we multiply 810 by 0.2642. So:

810 * 0.2642 = 214.00 gallons

"To generate the electricity you​ used, 214.00 gal is needed."

7 0
3 years ago
Ball B, with a mass of 30kg, is moving to the left at -10 m/s. With what velocity should Ball A, with a mass of 10 kg, move to t
tangare [24]
Initially, Ball A of 10 kg will have velocity x, while Ball B of 30 kg has velocity -10 m/s.
After collision, Ball A will have a velocity of -30 m/s, while Ball B will have velocity 10 m/s. We assume their masses do not change.
(10 kg)(x m/s) + (30 kg)(-10 m/s) = (10 kg)(-30 m/s) + (30 kg)(10 m/s)
10x - 300 = -300 + 300
x = 30 m/s (to the right)
5 0
3 years ago
Simplify: 3x²-3x -x (2x +4x)​
DENIUS [597]

Answer:

I think it's 25/30.

Step-by-step explanation:

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What are all the like terms for -5x? a:0.5. B:7.5x. C:-5. D:-x. E:2/3x.
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B,d, and e, because they all have the same variable, it doesn’t matter if they’re negative or positive
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2 years ago
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