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olasank [31]
3 years ago
14

Simplify. Question is in the picture.

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
3 0

√(12/27)

= √(4 * 3) / √(9 * 3)

= 2√3 / 3√3

= 2/3

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If y=12 when x=22 what is y when x=45
VLD [36.1K]

Answer:

y = 35

Step-by-step explanation:

3 0
2 years ago
In an article regarding interracial dating and marriage recently appeared in a newspaper. Of 1719 randomly selected adults, 311
Bingel [31]

Answer:

Step-by-step explanation:

Hello!

The parameter of interest in this exercise is the population proportion of Asians that would welcome a person of other races in their family. Using the race of the welcomed one as categorizer we can define 3 variables:

X₁: Number of Asians that would welcome a white person into their families.

X₂: Number of Asians that would welcome a Latino person into their families.

X₃: Number of Asians that would welcome a black person into their families.

Now since we are working with the population that identifies as "Asians" the sample size will be: n= 251

Since the sample size is large enough (n≥30) you can apply the Central Limit Theorem and approximate the variable distribution to normal.

Z_{1-\alpha /2}= Z_{0.975}= 1.965

1. 95% CI for Asians that would welcome a white person.

If 79% would welcome a white person, then the expected value is:

E(X)= n*p= 251*0.79= 198.29

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.79*0.21=41.6409

√V(X)= 6.45

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

198.29±1.965*6.45

[185.62;210.96]

With a 95% confidence level, you'd expect that the interval [185.62; 210.96] contains the number of Asian people that would welcome a White person in their family.

2. 95% CI for Asians that would welcome a Latino person.

If 71% would welcome a Latino person, then the expected value is:

E(X)= n*p= 251*0.71= 178.21

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.71*0.29= 51.6809

√V(X)= 7.19

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

178.21±1.965*7.19

[164.08; 192.34]

With a 95% confidence level, you'd expect that the interval [164.08; 192.34] contains the number of Asian people that would welcome a Latino person in their family.

3. 95% CI for Asians that would welcome a Black person.

If 66% would welcome a Black person, then the expected value is:

E(X)= n*p= 251*0.66= 165.66

And the Standard deviation is:

V(X)= n*p*(1-p)= 251*0.66*0.34= 56.3244

√V(X)= 7.50

You can construct the interval as:

E(X)±Z₁₋α/₂*√V(X)

165.66±1.965*7.50

[150.92; 180.40]

With a 95% confidence level, you'd expect that the interval [150.92; 180.40] contains the number of Asian people that would welcome a Black person in their family.

I hope it helps!

5 0
3 years ago
Whats the answer, to the question below
NISA [10]

The answer to this problem is 5.

6 0
3 years ago
Read 2 more answers
FOR 10 POINTS WILL MARK BRAINLIEST It costs $175 to rent a jet ski for 2 hours. It costs $300 to rent a jet ski for 2 hours. It
Cerrena [4.2K]
Y=$175+x I think this is it? one half of 175 is 87.5 so you know.
8 0
3 years ago
Value of expression a (a2 + a +1) + 5 for a = 0 is ___________
jeyben [28]

Answer:

5

Step-by-step explanation:

0(0×2 + 0 + 1) + 5

0(0+0+1)+5

0 + 0 + 0 +5

= 5

8 0
2 years ago
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