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Law Incorporation [45]
3 years ago
12

You randomly survey students about year-round school. The results are shown in the graph.

Mathematics
1 answer:
Sergio [31]3 years ago
6 0

Answer:

27% and 37%

Step-by-step explanation:

Percentage of students who oppose the year-round school = 68%

Percentage of students who support the year-round school = 32%

Margin of error = ± 5%

We have to set up the absolute valued equation to find the range(least and greatest) percentages of students who could be in favor of year-round school.

Since, the percentage of students who support the year-round school is 32% and the margin of error is 5%, this means, the difference between 32% and the least and greatest possible percentages is 5%. It can be either +5% or -5%

This thing can be expressed as absolute valued equation as:

| x - 32 | = 5

Here x represents the least and greatest percentages.

Expanding the equation, we can write:

x - 32 = -5                or                x - 32 = 5

x = -5 + 32                or               x = 5 + 32

x = 27%                                       x= 37%

This means the least percentage of students who be in favor is 27% and the greatest percentage of students is 37%.

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Answer:

The estimation answer is about 6

The answer that is not estimated is 5 8/9

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4 years ago
Which system of linear inequalities has the point (3,2) in its solution set?
chubhunter [2.5K]
None of the answers in the picture are the correct answer.
y > -2
y >= 2/3x -4
would be the correct answer here.
The reasoning is both the equations should have (3,2) as a possible solution.
For the first inequality y has to greater than -2 because the given point has 2 as the y coordinate.
also putting (3,2) in y = 2/3x - 4, we observe that the equation becomes 2 = -2. So there must be a >= sign in the second inequality.
8 0
3 years ago
Read 2 more answers
A garden has width of <img src="https://tex.z-dn.net/?f=%5Csqrt13" id="TexFormula1" title="\sqrt13" alt="\sqrt13" align="absmidd
inessss [21]

Answer:

perimeter of the garden=2(length+width)

=2(7√13+√13)

=2(8√13)

=16√13

4 0
3 years ago
Gambles are independent, and each one results in the playerbeing equally likely to win or lose 1 unit. Let W denote the netwinni
san4es73 [151]

Answer:

P{W>0}=0.5

P{W=0}=0.25

E{W}=0

Step-by-step explanation:

<u>Given:</u>

Gambles are independent i.e. each player is equally likely to win or lose 1 unit. OR each player has equal probability to win or lose 1 unit.

Let W denote the net winnings of a gambler whose strategy is to stop gambling immediately after his first win.

Then

<u>A.P{W>0}=?</u>

P{W>0}=0.5, because each player is equally likely to win or lose on first gamble. i.e there is equal chances for winning or losing on the first gamble.

<u>B.P{W<0}=?</u>

for P{W<0} we need to find P{W=0} first as;

P{W=0}=0.25

As there is equal probability to win or lose, after first win, if you want to finish gamble with no profit (equal number of lose and win) then if you losing, you have equal probability to win or lose so to finish your game with P=0 your probability is 0.25 (half of 0.5)

P{W<0} means net lose which is equal to total probability minus probability of profit and probability of net profit equal to zero.

i.e. P{W<0}=1-P{W=0}-P{W>0}

P{W<0}=1-0.25-0.5=0.25

<u>C.E{W}=?</u>

E{W}=P{W>0}*{W>0}+P{W<0}*{W<0}+P{W=0}*{W=0}

E{W}=0.5*(1)+0.5(-1)+0.25*(0) (for any value of W,P{W>0}*{W>0}+P{W<0}*{W<0}=0, because sum of same positive and negative numbers is zero)

E{W}=0

8 0
3 years ago
7) c/a=d-r, for a<br><br> thanks
elena-14-01-66 [18.8K]

Answer:

a = c/(d - r)

Step-by-step explanation:

Multiply both sides by a

(c/a)a = (d - r)*a  Notice how this is written. You need to introduce brackets on the right because both d and r are multiplied by a.

c = (d - r)*a                

Divide both sides by (d - r)

c/(d - r) = a*(d - r)/(d - r)

c/(d - r) = a

4 0
3 years ago
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