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andriy [413]
3 years ago
9

How many moles of Al(CN)3 are in 251 g of the compound?

Chemistry
1 answer:
Margaret [11]3 years ago
5 0

Answer:

251 g of compound contain 2.39 moles.

Explanation:

Given data:

mass of compound Al(CN)3 = 251 g

moles = ?

Solution:

First of all we will calculate the molar mass of given compound.

molar mass of Al(CN)3 = 26.98 + (26 × 3)

molar mass of Al(CN)3 = 105 g/mol

Formula:

number of moles = mass/ molar mass

number of moles = 251 g / 105 g/mol

number of moles = 2.39 mole

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The concentration of protein in a urine sample is calculated to be 2.77 μg/mL. What is the concentration of this solution in uni
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Answer:

The concentration of this solution in units of pounds per gallon is 2.776*10^{-5} \frac{lb}{gal}

Explanation:

Units of measurement are established models for measuring different quantities. The conversion of units is the transformation of a quantity, expressed in a certain unit of measure, into an equivalent one, which may or may not be of the same system of units.

In this case, the conversion of units is carried out knowing that 1 μg are equal to 2.205*10⁻⁹ Lb and  1 mL equals 0.00022 Gallons. So

2.77 \frac{ug}{mL} = \frac{2.77 ug}{mL}

If 1 μg equals 2.205*10⁻⁹  lb, 2.77 μg how many lb equals?

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So, 2.77 μg= 6.10785*10⁻⁹ lb

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