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Levart [38]
2 years ago
15

3/8 of flower garden are red and 3/6 are yellow which is greater, less than or equal

Mathematics
1 answer:
kirill115 [55]2 years ago
3 0

Answer:

3/8 < 3/6

This is because, when the common denominator (24) is found, the fractions are 9/24 (red) and 12/24 (yellow).

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Cameron drives a semitruck for Haulin' Harry's Trucking Company. He earns $0.45 for every mile he drives. If Cameron drove 827.4
ANEK [815]

Answer:

$372.330

Step-by-step explanation:

if 1 mile = $0.45 and you want to find out 827.4 miles

you should multiple $0.45 × 872.4

1 mile : $0.45

827.4 × $0.45 = 372330

827.4 : $372.330

3 0
3 years ago
Anybody have an answer?
lyudmila [28]

(3+2)^2+(5+4)^2=x^2\\ 5^2+9^2=x^2\\ 25+81=x^2\\ x^2=106\\ x\approx10.3

7 0
3 years ago
AB ≅ BC and AD ≅ CD What additional information would make it immediately possible to prove that triangles AXB and CXB are congr
kobusy [5.1K]

It is given that, B ≅ BC and AD ≅ CD  

We need BD perpendicular to AC, then only we can say  triangles AXB and CXB are congruent using the HL theorem.

If BD perpendicular to AC, means that AB and CB are the hypotenuse of triangles AXB and CXB respectively.

from the given information ABCD is a square

If BD and AC bisect each other then AX = CX

Then only we can  immediately possible to prove that triangles AXD and CXD are congruent by SSS congruence theorem

5 0
3 years ago
Read 2 more answers
Please Help. 25 points. <br>​
vodomira [7]

Answer:

\boxed{x = 7, y = 9, z = 68}

Step-by-step explanation:

We must develop three equations in three unknowns.

I will use these three:

\begin{array}{lrcll}(1) & 8x + 13y +7 & = & 180 & \\(2)& 9x - 7 + 13y +7 & = & 180 & \\(3)& 8x + 5y - 11 + z & = & 180 &\text{We can rearrange these to get:}\\(4)& 8x + 13y & = & 173 &\\(5) & 9x + 13y & = & 180 & \\(6)& 8x + 5y + z & = & 169 & \\(7)& x & = & \mathbf{7} & \text{Subtracted (4) from (5)} \\\end{array}

\begin{array}{lrcll}& 8(7) + 13y & = & 173 & \text{Substituted (7) into (4)} \\& 56 + 13y & = & 173 & \text{Simplified} \\& 13y & = & 117 & \text{Subtracted 56 from each side} \\(8)& y & =& \mathbf{9}&\text{Divided each side by 13}\\& 8(7) + 5(9) + z & = & 169 & \text{Substituted (8) and (7) into (6)} \\& 56 + 45 + z& = & 169 & \text{Simplified} \\& 101 + z& = & 169 & \text{Simplified} \\&z& = & \mathbf{68} & \text{Subtracted 101 from each side}\\\end{array}

\boxed{\mathbf{ x = 7, y = 9, z = 68}}

4 0
3 years ago
Help........... with this look
julsineya [31]
Hmmmmmm ok i know how to do this
3 0
3 years ago
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