Answer:
c
Step-by-step explanation:
<span><u>Answer
</u>
18 feet and 4.5 inches
<u>Explanation
</u>
You are going to use the concept of similar triangle.
∆CED≡∆CBA
This is because they share the angle at C and also they both have an angle of 90o.
Let EC = X, then BE = 2.5X. So, BE = (X + 2.5X) = 3.5X
The scale factor EC/BC=x/3.5x=2/7
EC/BC=ED/BA=2/7
BA=7/2×63 in
The height of the tree = 220.5 inches. This is equal 18 feet and 4.5 inches.
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Square root of 154m^2 = 12.5~
So adding 1.5 to 12.5 and subtracting 1.5 to 12.5 gives us 11 and 14
Your dimensions are 11x14
Brainliest?
Thanks!
Answer:
97.98
Step-by-step explanation:
The area of the parallelogram PQR is the magnitude of the cross product of any two adjacent sides. Using PQ and PS as the adjacent sides;
Area of the parallelogram = |PQ×PS|
PQ = Q-P and PS = S-P
Given P(0,0,0), Q(4,-5,3), R(4,-7,1), S(8,-12,4)
PQ = (4,-5,3) - (0,0,0)
PQ = (4,-5,3)
Also, PS = S-P
PS = (8,-12,4)-(0,0,0)
PS = (8,-12,4)
Taking the cross product of both vectors i.e PQ×PS
(4,5,-3)×(8,-12,4)
PQ×PS = (20-36)i - (16-(-24))j + (-48-40)k
PQ×PS = -16i - 40j -88k
|PQ×PS| = √(-16)²+(-40)²+(-88)²
|PQ×PS| = √256+1600+7744
|PQ×PS| = √9600
|PQ×PS| ≈ 97.98
Hence the area of the parallelogram is 97.98
