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3 years ago

8

NEED HELP FAST!!! Determine the momentum: An electron (m= 9.1 x 10-31 kg) moving at 2.18 x 106 m/s (as if it were in a Bohr orbi

t in the H atom)

2 answers:

Greeley [361]3 years ago

7 0

Answer:

fuçk you

Step-by-step explanation:

astra-53 [7]3 years ago

5 0

Answer:

p= (9.1 x 10^-31)(2.18 x 10^6) p = 1.9 x 10^-22kg*m/s

Step-by-step explanation:

for i said so

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A number is decreased by seven. Then, the new number is multiplied by 3 to get an answer of -9. What is the original number? A.

rusak2 [61]

Answer:

The answer is c

Step-by-step explanation:

You have to do everything backwards,

-9 divide it by 3 to get -3, then add seven to that answer

5 0

3 years ago

Read 2 more answers

Solve using long division <br> Please

madreJ [45]

1. $Solution,\frac{2x^3+4x^2-5}{x+3}:\quad 2x^2-2x+6-\frac{23}{x+3}$

$Steps:$

$\mathrm{Divide}\:\frac{2x^3+4x^2-5}{x+3}:\quad \frac{2x^3+4x^2-5}{x+3}=2x^2+\frac{-2x^2-5}{x+3}$

$\mathrm{Divide}\:\frac{-2x^2-5}{x+3}:\quad \frac{-2x^2-5}{x+3}=-2x+\frac{6x-5}{x+3}$

$\mathrm{Divide}\:\frac{6x-5}{x+3}:\quad \frac{6x-5}{x+3}=6+\frac{-23}{x+3}$

$\mathrm{Simplify}, =2x^2-2x+6-\frac{23}{x+3}$

$\mathrm{The\:Correct\:Answer\:is\:2x^2-2x+6-\frac{23}{x+3}}$

2. $Solution, \frac{4x^3-2x^2-3}{2x^2-1}:\quad 2x-1+\frac{2x-4}{2x^2-1}$

$Steps:$

$\mathrm{Divide}\:\frac{4x^3-2x^2-3}{2x^2-1}:\quad \frac{4x^3-2x^2-3}{2x^2-1}=2x+\frac{-2x^2+2x-3}{2x^2-1}$

$\mathrm{Divide}\:\frac{-2x^2+2x-3}{2x^2-1}:\quad \frac{-2x^2+2x-3}{2x^2-1}=-1+\frac{2x-4}{2x^2-1}$

$\mathrm{The\:Correct\:Answer\:is\:2x-1+\frac{2x-4}{2x^2-1}}$

$\mathrm{Hope\:This\:Helps!!!}$

$\mathrm{-Austint1414}$

4 0

3 years ago

juan has 12 muffins he puts one fourth of the muffins in a bag how many muffins does juan put in the bag

anyanavicka [17]

He put 3 in the bag because 12 divided by 4 is 3

3 0

3 years ago

Read 2 more answers

X + 11 = 3 so the equation

Mnenie [13.5K]

X+11=3
-11 -11
x=-8

you subtract 11 from both sides. then you got the answer.

8 0

3 years ago

Can i get help? Don’t really understand.

Rufina [12.5K]

First option: correct. This is because angles WOX and XOZ are supplementary, so

$m\angle WOX=180^\circ-104^\circ=76^\circ$

Second option: correct. By the inscribed angles theorem, we have

$m\angle XWZ=m\angle XYZ=\dfrac{113^\circ}2=56.5^\circ$

Angles WOX and YOZ are congruent because they form a vertical pair; they both have measure 76 degrees. This means angles WXY and WZY are also congruent, since the interior angles of any triangle sum to 180 degrees in measure. Therefore triangles WXO and YZO form a side-side-side pair, and all SSS triangles are similar.

Third option: not correct. There is a theorem (not sure what the name is) regarding intersecting chords that asserts the average of the measures of arcs WY and XZ is the same as the measure of angle XOZ. This means

$\dfrac{m\widehat{WY}+113^\circ}2=104^\circ\implies m\widehat{WY}=95^\circ$

Fourth option: not correct. This is because arcs WX and XZ are not "supplementary" in the sense that they do not form a semicircle and their measures do not add to 180 degrees. We know this because it's clear that point O is not the center of the circle. If it was, then angle XOZ would be a central angle and its measure would be the same as the arc XZ it subtends.

Fifth option: correct. The theorem mentioned in the assessment of the third option makes itself useful here. We have

$\dfrac{m\widehat{WX}+m\widehat{YZ}}2=m\angle WOX\implies m\widehat{WX}+m\widehat{YZ}=2\cdot76^\circ=152^\circ$

4 0

3 years ago