Answer:
Step-by-step explanation:
Daily temp(in F) Cakes sold
42 39
45 52
48 31
54 61
59 72
62 35
64 61
65 34
67 58
75 45
84 24
To find whether there is an association between these two let us find the correlation coefficient between these two variables.
r=-0.1975
Since |r|<0.5, correlation is weak.
Let us test the hypothesis r =0
H0:r=0
Ha:r not equals 0
Test statistic = 
p =0.298
Since p value >0.10, at 90% significance level we accept that there is no association.
When you round 4, 398, 202 to the nearest 100 it means to ignore the 4,398 and just look at 202. You could either round to 200 or 300 since you want to round to the nearest 100. Since the ones place is 2, you round the number to 200.
Answer: 4,398,200
Answer:
Step-by-step explanation:
From the information given,
Number of personnel sampled, n = 85
Mean or average = 6.5
Standard deviation of the sample = 1.7
We want to determine the confidence interval for the mean number of years that personnel spent in a particular job before being promoted.
For a 95% confidence interval, the confidence level is 1.96. This is the z value and it is determined from the normal distribution table. We will apply the following formula to determine the confidence interval.
z×standard deviation/√n
= 1.96 × 6.5/√85
= 1.38
The confidence interval for the mean number of years spent before promotion is
The lower end of the interval is 6.5 - 1.38 = 5.12 years
The upper end is 6.5 + 1.38 = 7.88 years
Therefore, with 95% confidence interval, the mean number of years spent before being promoted is between 5.12 years and 7.88 years
Answer:
(x, y - 6)
Step-by-step explanation: