<span>ds=<span>√<span>1+<span><span>(<span><span>dy</span><span>dx</span></span>)</span>2</span></span></span><span>dx</span>=<span>√<span>1+<span>14</span><span>(<span>x4</span>−2+<span>1<span>x4</span></span>)</span></span></span><span>dx</span></span>
<span>=<span>√<span><span>14</span><span>(<span>x4</span>+2+<span>1<span>x4</span></span>)</span></span></span><span>dx</span>=<span>√<span><span>1<span>22</span></span><span><span>(<span>x2</span>+<span>1<span>x2</span></span>)</span>2</span></span></span><span>dx</span></span>
<span>=<span>12</span><span>(<span>x2</span>+<span>1<span>x2</span></span>)</span><span>d<span>x</span></span></span>
To determine the maxima and minima of the polynomial, differentiate the given based on x and equate to 0.
C(x) = 400x - 0.2x²
dC(x) / dt = 400 - 0.4 x = 0
The value of x is 1000. This is the value of the maxima. As the value of C(x) continously becomes lesser as the value of x is set higher, the minima is not identified. Substitute x to the original equation,
C(x) = (400)(1000) - 0.2(1000²) = $ 200,000
Thus, the answer is letter B.
Answer:
1: $92000 2: 52000 + 4000t= current salary
Step-by-step explanation:
1: simple arithmetic, 52000 + 4000(10)=92000
2: equation is formed as InitialSalary + 4000*(years at company) = New Salary
or with other variables, 52000+4000*t=N