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Ulleksa [173]
3 years ago
10

JK in the coordinate plane has endpoints with coordinates (-4, 11) and (8,

Mathematics
1 answer:
atroni [7]3 years ago
3 0

Answer:

(0, 7)

Step-by-step explanation:

Given:

J(-4, 11)

K(8, -1)

JP:JK = 1/3

Required:

Coordinates of P

SOLUTION:

Use the formula, (x, y) = (x_1 + k(x_2 - x_1), y_1 + k(y_2 - y_1)) to find the coordinates of point P, that partition the segment JK into the ratio 1/3.

Let,

J(-4, 11) = (x_1, y_1)

K(8, -1) = (x_2, y_2)

k = \frac{1}{3}

Thus, plug in the values as follows:

P(x, y) = (-4 + \frac{1}{3}(8 -(-4)), 11 + \frac{1}{3}(-1 - 11)

P(x, y) = (-4 + \frac{1}{3}(12), 11 + \frac{1}{3}(-12)

P(x, y) = (-4 + \frac{12}{3}, 11 + \frac{-12}{3})

P(x, y) = (-4 + 4,  11 + (-4)

P(x, y) = (0, 7)

The coordinates of point P, are (0, 7)

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Answer:

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Step-by-step explanation:

<u><em>Explanation:-</em></u>

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ii)

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The point( 3 , 1/125)  is satisfies the  given graph  g(x) = (\frac{1}{5} )^{x}

                 

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