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Pani-rosa [81]
3 years ago
14

Is it possible for a quadrilateral to have only 2 right angles

Mathematics
2 answers:
Mice21 [21]3 years ago
5 0
No because it's a square it has to have 4 right angles.
yan [13]3 years ago
3 0
Yes because quadrilateral is the angle who have 2
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Please help !!!!!!!!!!
Vesna [10]

Answer:

(2, 2) states x=2 and y=2

Considering the inequality:

y\leq 4x-6

Is y less than or equal to 2 when x = 2?

2\leq 4(2)-6\\2\leq 8-6\\2\leq 2\\

Yes, (2, 2) is a solution for the inequality.

4 0
3 years ago
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vichka [17]
This is 4702 hope it helps
6 0
3 years ago
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Reality Check 4: Bringing the NBA into Math 0980
rusak2 [61]
Is this a question or do I have to search up this sentence to help you?
6 0
3 years ago
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5 1/3 + x = 2 1/2. Use least common denominator or easiest common denominator. Please work out
julia-pushkina [17]

Answer:

The answer is x = -17/6.

Step-by-step explanation:

Given:

5 1/3 + x = 2 1/2 . Using least common denominator.

Now, to solve the equation:

5\frac{1}{3}+x=2\frac{1}{2}

=\frac{16}{3} +x=\frac{5}{2}

Subtracting both sides from 16/3 we get:

x=\frac{5}{2}- \frac{16}{3}

Now, the least common denominator of 2 and 3 is 6.

So, we using this we calculate:

x=\frac{5\times 3-16\times 2}{6}

x=\frac{15-32}{6}

x=\frac{-17}{6}

Therefore, the answer is x = -17/6.

7 0
3 years ago
Solve question 3 for <br> 41 points
Sever21 [200]

Answer:

(2)

Step-by-step explanation:

Our logarithmic expression is: ln(\frac{\sqrt{e} }{y^3} ).

Remember the logarithmic property that ln(a/b) = lna - lnb. So, we can write this as:

ln(\frac{\sqrt{e} }{y^3} )=ln(\sqrt{e} )-ln(y^3)

Also, we can write square roots as powers of one-half, so √e = e^{1/2}. There's another log property that: ln(a^b)=b*ln(a). We can apply that here for both the √e and the y³:

ln(\sqrt{e} )-ln(y^3)=\frac{1}{2} ln(e)-3ln(y)

Finally, note that ln(e) is just 1, so we have:

\frac{1}{2} ln(e)-3ln(y)=\frac{1}{2} -3ln(y)=\frac{1-6ln(y)}{2}

The answer is thus (2).

<em>~ an aesthetics lover</em>

7 0
3 years ago
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