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pychu [463]
3 years ago
11

(6) Give the equation of the line passing through the points (1,5) and (-2, 6) in

Mathematics
1 answer:
Bas_tet [7]3 years ago
8 0

Answer:

⅓x + y = 5⅓

or

⅓x + y = 5.3333333

or

⅓x + y = 16/3

Step-by-step explanation:

Solve for slope using rise/run

Y2 - Y1 / X2 - X1

(6) - (5) / (-2) - (1)

1 / -3

Slope: -⅓

y = -⅓x + b

solve for b using one of the points

I'll be using (1,5)

Substitute the point into the equation

5 = -⅓(1) + b

5 = -⅓ + b (add ⅓ to both sides)

+⅓ +⅓

5⅓ = b

5⅓ can also be written as 16/3 or 5.333333

The equation is now:

y = -⅓x + 5⅓

Convert to standard form by adding ⅓x to both sides

y = -⅓x + 5⅓

+⅓x +⅓x

Solution: ⅓x + y = 5⅓

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You have been asked to analyze the popcorn recipes of three different local theatres in order to figure out which theatre has th
svlad2 [7]

Answer:    The ratio value of oil to popcorn kernels for theatre C is 6 / 32 = 3 / 16.

Step-by-step explanation: Given that the manager of Theatre A says that they usually go through about 15 cups of popcorn kernels and about 5 cups of oil each weeknight.

Then, the ratio value of oil to popcorn kernels for theatre A is 5 / 15 = 1 / 5.

Given that the manager of Theatre B says that they order 18 cups of oil and 72 cups of popcorn kernels each week.

Then, the ratio value of oil to popcorn kernels for theatre B is 18 / 72 = 1 / 4.

Given that the manager of Theatre C says that their concessions use 6 cups of oil and 32 cups of popcorn kernels on a busy Saturday.

Then, the ratio value of oil to popcorn kernels for theatre C is 6 / 32 = 3 / 16.

3 0
2 years ago
Not sure if any of this is correct, but it’s what I got so far
Irina18 [472]

Problem 1 is correct. You use the pythagorean theorem to find the hypotenuse.

==================================================

Problem 2 has the correct answer, but one part of the steps is a bit strange. I agree with the 132 ft/sec portion; however, I'm not sure why you wrote \frac{1 \text{ sec}}{132 \text{ ft}}=\frac{0.59\overline{09}}{78 \text{ ft}}*127 \text{ ft}

I would write it as \frac{1\text{ sec}}{132 \text{ ft}}*127 \text{ ft} = \frac{127}{132} \text{ sec} \approx 0.96 \text{ sec}

==================================================

For problem 3, we first need to convert the runner's speed from mph to feet per second.

17.5 \text{ mph} = \frac{17.5 \text{ mi}}{1 \text{ hr}}*\frac{1 \text{ hr}}{60 \text{ min}}*\frac{1 \text{ min}}{60 \text{ sec}}*\frac{5280 \text{ ft}}{1 \text{ mi}} \approx 25.667 \text{ ft per sec}

Since the runner needs to travel 90-12 = 78 ft, this means\text{time} = \frac{\text{distance}}{\text{speed}} \approx \frac{78 \text{ ft}}{25.667 \text{ ft per sec}} \approx 3.039 \text{ sec}

So the runner needs about 3.039 seconds. In problem 2, you calculated that it takes about 0.96 seconds for the ball to go from home to second base. The runner will not beat the throw. The ball gets where it needs to go well before the runner arrives there too.

-------------

The question is now: how much of a lead does the runner need in order to beat the throw?

Well the runner needs to get to second base in under 0.96 seconds.

Let's calculate the distance based on that, and based on the speed we calculated earlier above.

\text{distance} = \text{rate}*\text{time} \approx (25.667 \text{ ft per sec})*(0.96 \text{ sec}) \approx 24.64032 \text{ ft}

This is the distance the runner can travel if the runner only has 0.96 seconds. So the lead needed is 90-24.64032 = 65.35968 feet

This is probably not reasonable considering it's well over halfway (because 65.35968/90 = 0.726 = 72.6%). If the runner is leading over halfway, then the runner is probably already in the running motion and not being stationary.

As you can see, the runner is very unlikely to steal second base. Though of course such events do happen in real life. What may explain this is the reaction time of the catcher may add on just enough time for the runner to steal second base. For this problem however, we aren't considering the reaction time. Also, not all catchers can throw the ball at 90 mph which is quite fast. According to quick research, the MLB says the average catcher speed is about 81.8 mph. This slower throwing speed may account for why stealing second base isn't literally impossible, although it's still fairly difficult.

5 0
3 years ago
What is 7 2/3 - 1 1/3
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Change both fractions into improper fractions then subtract Ans=19/3 R 6 1/3
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3 years ago
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I would either go with a or c
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melisa1 [442]
Answer is 34 ft squared
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