Answer:
11 ;
Step-by-step explanation:
Given the data:
30 27 22 25 24 25 24 15 35 35 33 52 49 10 27 18 20 23 24 25 30 24 24 24 18 20 25 27 24 32 13 13 21 2 37 35 32 33 29 3 28 28 25 29 31
Number of classes = 5
Class width : Range / number of classes
Class width = (maximum - minimum) / 5
Class width = (52 - 2) / 5 = 50/5 = 10 + 1 = 11
For the frequency table showing class limits, class boundaries, midpoints, frequencies, relative frequencies, and cumulative frequencies and histogram
Kindly check attached picture
If 30% were perfect, 70% were not perfect. So we know that 70% of the total number of photographs is 210.
p(70/100)=210 multiply both sides by 100
70p=21000 divide both sides by 70
p=300
So there are 300 photographs in all.
The answer is A- between 8 m& 12m
Answer:
Step-by-step explanation:
Since tan is equal to the opposite over adjacent
Tan(angle G)= HI/IG
Answer:
0 2
1 4 ⟌ 3 7
- 0
3 7
- 2 8
9
2 r 9
for 37 divided by 14
0 7
1 3 ⟌ 9 6
- 0
9 6
- 9 1
5
7 r 5
for 96 divided by 13
0 2 0
4 1 ⟌ 8 5 8
- 0
8 5
- 8 2
3 8
- 0
3 8
for 858 divided by 41
20 r 38
Step-by-step explanation:
