All categories

3 years ago

Greatest common factor of 66 and 77, will mark brainlist to the first 1 who gets it right

Mathematics

2 answers:

fiasKO [112]3 years ago

5 0

Answer:

D (11)

Step-by-step explanation:

77 / 11 = 7

66/11 = 6

sergiy2304 [10]3 years ago

3 0

Answer:

the factors and prime factorization of 66 and 77. The biggest common factor number is the GCF number. So the greatest common factor 66 and 77 is 11.

Step-by-step explanation:

You might be interested in

Find the selling price. Round to the nearest cent.

Mrac [35]

10% of 13 is 1.3 so 13+1.3= 14.3

4 0

2 years ago

Read 2 more answers

12 pleaseeee and thanksss

Svetlanka [38]

Answer:

Step-by-step explanation:

0.5-8y= 72

7 0

2 years ago

I xyzdS trong đó S là phần mặt 2 2 z x y nằm giữa hai mặt phẳng z = 0 và z = 1

Anni [7]

Step-by-step explanation:

ewtjsgmsgmgdmgqrhwtjwthwtj

$= . { {y1 {11.1 \times 3 { { {?}^{?} }^{?} }^{?} }^{?} }^{2} }^{2}$

vadbstjtwjsgjdgndymarhedvdhstjwtktwdgharjqrjwrjgjtkstjtsjafbsfnafhafbsfhtshqwdgjwjdjdnnxnxifjnrnthrwhst

$22 {y)bvzv \cot( \beta log( \sec( log( \cot( \sec( \beta \alpha \pi \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( \sec( log(?) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) ) \times \frac{?}{?} }^{2}$

hfzbcEdfgaywjshhsbxbxbxb. seznnxndndnndnxnbxhxududhbdxhhbxhjxjdbnzjsnsnnznzidnxnsbnzjxldkdjdnbx

4 0

2 years ago

Consider the sets A={1,3,5,7} and B={11,13,15,21}.

katovenus [111]

Those should be odd integers if I’m wrong let Me know and I’ll fix it for you

4 0

3 years ago

How to solve these 3 problems

Bingel [31]

Answer:

a. decay; b. growth; c. decay; d. neither
r = 4; a = 1; y = 1·4^x
a. an = 3(5^(n-1)); b. f(x) = (3/5)(5^x); c. exponential growth; d. y-intercept: 3/5; first term: 3.

Step-by-step explanation:

There are two kinds of exponential problems here.

exponential functions of the form f(x) = a·b^x
exponential sequences of the explicit form an = a1·r^(n-1)

The second problem gives you a table that suggests the sequence form, but it asks for the exponential function form. The third problem does something similar.

In an exponential function of the form f(x) = a·b^x, the function grows if b>1 and decays if b<1. Using this check, we can easily answer ...

a. 0.4 < 1 . . . decay

b. 1.3 > 1 . . . growth

c. 1/2 < 1 . . . decay

d. 1 = 1 . . . neither growth nor decay; the function is constant: j(x) = 1.

The value of x is given starting at 1, so we can consider this a geometric sequence. The common ratio is r = 16/4 = 4. The first term is a1 = 4, so the explicit formula for the sequence is ...

an = 4·4^(n-1)

When this is expanded to get rid of the constant in the exponent, we have ...

an = 4·(4^n)·(4^-1) = 1·4^n

We recognize this form as matching the functional form f(x) = a·r^x. The multiplier of the exponential factor is a=1. In summary, ...

r = 4; a = 1; f(x) = 1·4^x

The first term of this geometric sequence is a1 = 3. The common ratio is r = 15/3 = 5. Using the explicit formula, we have ...

a. explicit form: an = 3·5^(n-1)

Using the method of question 2 to write the functional form, we find ...

an = 3(5^n)(5^-1) = (3/5)(5^n)

b. functional form: f(x) = (3/5)(5^x)

c. function family: exponential growth functions

d. y-intercept: (3/5) . . . . read this from the f(x) form

1st term: the first term listed in the given sequence is 3

_____

Additional comment

The "y-intercept" of a sequence is irrelevant (undefined), as the sequence term numbering starts with 1, not 0. The domain of the explicit formula is natural numbers, which does not include 0.

Similarly, the "first term" of a function f(x) needs further definition. Here, we've answered the question by saying the first term is f(1). There is no conventional definition of a "first term" for a continuous function.

3 0

2 years ago