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KengaRu [80]
3 years ago
11

Complete the following proof.

Mathematics
1 answer:
frozen [14]3 years ago
8 0

Answer:

A tangent to a circle is a line intersecting the circle at exactly one point which is called point of tangency or tangency point. Also, radius from the center of the circle to the point of tangency is always perpendicular to the tangent line.

Here, O is the center of the circle and B is the point on the circumference of the circle,

⇒ OB is the radius of the given circle,

Also, BD is the tangent line for which B is the tangency point,

⇒ OB ⊥ BD ⇒ AB ⊥ BD ( Because, AOB is a straight line )

Similarly,

AB ⊥ AC

Since, if two lines are perpendicular to the same line then they are parallel to each other,

⇒ AC ║ BD

Hence, proved.

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43 divided by 4759 and 69 divided by 6267
Goshia [24]
43÷4759=0.0090355117 and 69÷6267=0.0110100527 is your answers
6 0
4 years ago
Pls help me with this question and pls don't answer if you don't know. thank you,
polet [3.4K]

Answer:

I apologize if this was poorly explained. The explanation for each is below the angle.

Since these triangles are in a rectangle, The top and bottom triangles are congruent, and the left and right triangles are congruent. All 4 triangles are also Isosceles. (Two equal sides/angles)

m<1= 59

(Left and right triangles are congruent)

m<2=31

(Top and bottom triangles are congruent)

m<3= 59

(Directly across from the other 59)

m<4=31

(Each of the rectangles corner angles totals to 90 degrees, therefore making this angle 31 degrees.)

m<5=31

(Since the triangles are isosceles, this angle is also 31)

m<6= 59

(Since m<5 is 31, this angle is 59.)

m<7=118

{(Two other angles in the triangle) 31+31= 62 180-62= 118)}

m<8=62

{(Two other angles in the triangle)59+59= 118. 180-118= 62}

m<9=62

(This angle and m<8 are congruent.)

m<10=118

(This angle and m<7 are congruent.)

m<11=31

(Same reason as m<4)

I hope this helps!

8 0
3 years ago
. Suppose the weight of Chipotle burritos follows a normal distribution with mean of 450 grams, and variance of 100 grams2 . Def
mylen [45]

Complete Question

Suppose the weight of Chipotle burritos follows a normal distribution with mean of 450 grams, and variance of 100 grams2 . Define a random variable to be the weight of a randomly chosen burrito.

(a) What is the probability that a Chipotle burrito weighs less than 445 grams? (3 points)

(b) 20% of Chipotle burritos weigh more than what weight

Answer:

a

   P(X  <  445  )=  0.3085

b

  k = 458.42

Step-by-step explanation:

From question we are told that

     The population mean is \mu  =  450 \ g

      The variance is var =  100 \ g^2

      The  consider weight is  x =  445 \ g

The  standard deviation is mathematically represented as

     \sigma  = \sqrt{var}

substituting values

     \sigma  = \sqrt{ 100}

     \sigma  = 10

Given that weight of Chipotle burritos follows a normal distribution the  the probability that a Chipotle burrito weighs less than x grams is mathematically represented as

        P(X  <  x  ) =  P ( \frac{X  -  \mu }{\sigma }  < \frac{x  -  \mu }{\sigma }  )

Where  \frac{X - \mu }{\sigma } is  equal to z (the standardized values of the random number X )

So

     P(X  <  x  ) =  P (Z  < \frac{x  -  \mu }{\sigma }  )

substituting values

     P(X  <  445  ) =  P (Z  < \frac{445  -  450 }{10}  )

      P(X  <  445  ) =  P (Z

Now from the normal distribution table  the value for P (Z  is  

      P(X  <  445  ) =  P (Z

=>   P(X  <  445  )=  0.3085

Let the  probability  of the Chipotle burritos weighting more that k be 20% so  

       P(X  >  k  ) =  P ( \frac{X  -  \mu }{\sigma }  > \frac{k  -  \mu }{\sigma }  ) = 0.2

=>    P (Z> \frac{k  -  \mu }{\sigma }  ) = 0.2

=>    P (Z> \frac{k  -  450}{10 }  ) = 0.2

From the normal distribution table the value of z  for  P (Z> \frac{k  -  \mu }{\sigma }  ) = 0.2 is  

    z  =  0.8416

=>   \frac{k  -  450}{10 }  = 0.8416

=>   k = 458.42

       

6 0
3 years ago
Reduce the quotient to lowest terms <br> 3x/8y divided 9x/16y
Anna [14]
Evaluate.
Exact Form:
2/3
Decimal Form:
0.6∞
Hope this helps! :)
8 0
4 years ago
Round 14.81 to the nearest tenth
kiruha [24]

Answer: 14.8

Step-by-step explanation: If the number in the hundredths place is less than 5, you must round down. On the contrary, if that number is 5 or greater, you must round up. This applies for rounding to any place not just the tenths place. For example, if you were to round it to the ones place, the answer would be 15.

3 0
2 years ago
Read 2 more answers
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