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Lerok [7]
3 years ago
5

1.What are the values of the 6s in 36,621?

Mathematics
1 answer:
enot [183]3 years ago
8 0
1) The value of 6s in 36,621 are 6,000 and 600.

first 6 is in the thousands place value while the second 6 is in the hundreds place value.
6 x 1000 = 6,000 and 6 x 100 = 600

2) The first 4 is ten times greater than the second 4 is shown in 354,426

the first 4 is in the thousands place value while the second 4 is in the hundreds place value
4 x 1000 = 4000 and 4 x 100 = 400

based on the question the first 4, which is 4000, is ten times greater than the second 4, which is 400.
we can check if this statement is true either by dividing 4000 by ten or multiplying 400 by ten.

4000/10 = 400 ; 400 x 10 = 4000. therefor, out of the 4 numbers given, the correct one is 354,426

3) The relationship of the two 5s in 552 is shown in 500 ÷ 50 = 10

based on its place value, the first five is in the hundreds place and the second five is in the tens place.

500 ÷ 50 = 10. This equation states that 500 is ten times greater than 50.

4) In 2,077 the first 7 is greater than the second 7 by 10 times.

using place value, first 7 is in the tens place while second 7 is in the ones place.

first 7 is 70; second 7 is 7. we divide 70 by 7 to know how many number of times 70 is greater than 7.

70 ÷ 7 = 10 times.


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777dan777 [17]

Answer:

(a) The distribution of X=\sum\limits^{n}_{i=1}{X_{i}} is a Binomial distribution.

(b) The sampling distribution of the sample mean will be approximately normal.

(c) The value of P(\bar X>0.50) is 0.50.

Step-by-step explanation:

It is provided that random variables X_{i} are independent and identically distributed Bernoulli random variables with <em>p</em> = 0.50.

The random sample selected is of size, <em>n</em> = 100.

(a)

Theorem:

Let X_{1},\ X_{2},\ X_{3},...\ X_{n} be independent Bernoulli random variables, each with parameter <em>p</em>, then the sum of of thee random variables, X=X_{1}+X_{2}+X_{3}...+X_{n} is a Binomial random variable with parameter <em>n</em> and <em>p</em>.

Thus, the distribution of X=\sum\limits^{n}_{i=1}{X_{i}} is a Binomial distribution.

(b)

According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.  

The sample size is large, i.e. <em>n</em> = 100 > 30.

So, the sampling distribution of the sample mean will be approximately normal.

The mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu=p=0.50

And the standard deviation of the distribution of sample mean is given by,

\sigma_{\bar x}=\sqrt{\frac{\sigma^{2}}{n}}=\sqrt{\frac{p(1-p)}{n}}=0.05

(c)

Compute the value of P(\bar X>0.50) as follows:

P(\bar X>0.50)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{0.50-0.50}{0.05})\\

                    =P(Z>0)\\=1-P(Z

*Use a <em>z</em>-table.

Thus, the value of P(\bar X>0.50) is 0.50.

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64/100
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