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Vikki [24]
2 years ago
9

Factor completely: 7r^2− 64r + 64

Mathematics
1 answer:
poizon [28]2 years ago
8 0

Answer:

7r^2-64r+64

49r-64r+64

-15r+64

Step-by-step explanation:

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Lucky Charms are sold in boxes with an advertised mean weight of 20.5 oz. The standard deviation is known to be 2.25 oz. A consu
Alinara [238K]

Answer:

Set of hypothesis.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ =  20.5 oz

Sample mean, \bar{x} = 20.4 oz

Sample size, n = 50

Population standard deviation, σ =  2.25 oz

First, we design the null and the alternate hypothesis

H_{0}: \mu = 20.5\text{ oz}\\H_A: \mu < 20.5\text{ oz}

We use One-tailed z test(left tailed) to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{20.4 - 20.5}{\frac{2.25}{\sqrt{50}} } = -0.3142

Based on the significance level, we can make our decision and complete the hypothesis testing.

We may accept the null hypothesis or fail to accept depending on different significance level.

4 0
4 years ago
Which of these is correct?
icang [17]

Answer:

the second one

Step-by-step explanation:

4 0
3 years ago
Stanley is putting wallpaper strips on his bathroom walls that have a total area of 460 ft2. Each strip of wallpaper covers 22 s
leonid [27]
To get the answer you multiply giving the answer of 10,120.
4 0
4 years ago
Read 2 more answers
How many centimeters are in 15 yards?
Ann [662]

Answer:

1371.6 (cm) are in 15 yards

Step-by-step explanation:

1371.6 centimeters are in 15 yards since 1 yard is equal to 91.44.

8 0
3 years ago
Read 2 more answers
Jessie estimated the weight of his cat to be 12 pounds. The actual weight of the cat is 15 pounds.
Studentka2010 [4]

Answer:

20%

Step-by-step explanation:

% of error is given by the following formula:

% Error = \frac{|\textrm {Approx Value  - Exact Value}|}{\textrm {Exact Value}} \times 100

Now, Jessie estimated the weight of his cat to be 12 pounds i.e. Approximate value is 12 pounds.

Again, The actual weight of the cat is 15 pounds i.e. the exact value is 15 pounds.

Therefore, the % error = \frac{|12 - 15|}{15} \times 100 = \frac{3}{15} \times 100 = 20% (Answer)

5 0
3 years ago
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