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Blababa [14]
2 years ago
10

Two trains 150 miles apart are traveling toward each other along the same track. The first train goes 60 miles per hour; the sec

ond train rushes along at 90 miles per hour. A fly is hovering just above the nose of the first train. It buzzes from the first train to the second train, turns around immediately, flies back to the first train, and turns around again. It goes on flying back and forth between the two trains until they collide. If the fly's speed is 120 miles per hour, how far will it travel?
Mathematics
1 answer:
Nataly_w [17]2 years ago
3 0

Answer:

120 miles

Step-by-step explanation:

Distance = 150 miles

train 1 = 60 mph

train 2 = 90 mph

directions of trains = towards each other

Time to meet = 150/(60+90) = 150 miles / 150 mph = 1 hour

Speed of fly = 120 mph

Since fly has been flying for one hour, it travelled 120 miles.

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Sorry for the crumbled paper Can someone help me<br><br> Complete the chart
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5 0
2 years ago
Write the expression 53.7124 x 10^{3} as a single number
mars1129 [50]

Answer:

53712.4

Explanation:

\sf\rightarrow  53.7124\:x\:10^3

  • 10³ = 1000

\sf\rightarrow  53.7124\:x\:1000

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6 0
1 year ago
Read 2 more answers
Please answer these 4 math questions for me! Pretty easy! need then ASAP!!!!! I have to get them right or my life is doomed! (ca
Grace [21]

Answer:

Last one is 90 and -65, 3rd one is 120 feet i think, and i am 99% sure 2nd one is 129

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
The first aircraft has 51 more seats than the second aircraft. the third aircraft has 54 fewer seats than the second aircraft. i
NikAS [45]

Let a = aircraft 1 seats

Let b = aircraft 2 seats

Let c = aircraft 3 seats

From the information given above, let's make basic equations.

a=51+b

b=b

c=b-54

a+b+c=411

We can begin to plug in values we know.

51+b+b+b-54=411

3b-3=411

3b=414

b=138

We now know that the second aircraft has 138 seats. Now we can plug in this value to find the value of the other seats. Let's start with the first aircraft.

a=51+b

a=51+138

a=189

We now know that the first aircraft has 189 seats. Let's now finally solve for the third aircraft.

c=b-54

c=138-54

c=84

Finally, we know that aircraft 3 has 84 seats. To check our work, let's make sure that each of these values add up to 411.

a+b+c=411

189+138+84=411

411=411

This is true, therefore the values are correct.


Aircraft 1: 189 seats

Aircraft 2: 138 seats

Aircraft 3: 84 seats

4 0
3 years ago
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