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Illusion [34]
3 years ago
9

Consider the function f ( x ) = − 2 x 3 + 27 x 2 − 108 x + 9 . For this function there are three important open intervals: ( − [

infinity] , A ) , ( A , B ) , and ( B , [infinity] ) where A and B are the critical numbers. Find A and B
Mathematics
1 answer:
Darya [45]3 years ago
3 0

Answer:

<em>A=3 and B=6</em>

Step-by-step explanation:

<u>Increasing and Decreasing Intervals of Functions</u>

Given f(x) as a real function and f'(x) its first derivative.

If f'(a)>0 the function is increasing in x=a

If f'(a)<0 the function is decreasing in x=a

If f'(a)=0 the function has a critical point in x=a

As we can see, the critical points may define open intervals where the function has different behaviors.

We have

f ( x ) = - 2 x^3 + 27 x^2 - 108 x + 9

Computing the first derivative:

f' ( x ) = - 6 x^3 + 54 x - 108

We find the critical points equating f'(x) to zero

- 6 x^3 + 54 x - 108=0

Simplifying by -6

x^2 -9 x +18=0

We get the critical points

x=3,\ x=6

They define the following intervals

(-\infty,3),\ (3,6),\ (6,+\infty)

Thus A=3 and B=6

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Answer:

dy/dx = (cos y + y sin x) / (cos x + x sin y)

Step-by-step explanation:

y cos x = x cos y

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-y sin x + dy/dx cos x = -x sin y dy/dx + cos y

dy/dx (cos x + x sin y) = cos y + y sin x

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5 0
3 years ago
2y = 4x - 8 <br>3x + 2y = 6<br>graph​
Vinvika [58]

Answer:

  see attached

Step-by-step explanation:

I find it convenient to let a graphing calculator draw the graph (attached).

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If you're drawing the graph by hand, there are a couple of strategies that can be useful.

The first equation is almost in slope-intercept form. Dividing it by 2 will put it in that form:

  y = 2x -4

This tells you that the y-intercept, (0, -4) is a point on the graph, as is the point that is up 2 and right 1 from there: (1, -2). A line through those points completes the graph.

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The second equation is in standard form, so the x- and y-intercepts are easily found. One way to do that is to divide by the constant on the right to get ...

  x/2 +y/3 = 1

The denominators of the x-term and the y-term are the x-intercept and the y-intercept, respectively. If that is too mind-bending, you can simply set x=0 to find the y-intercept:

  0 +2y = 6

  y = 6/2 = 3

and set y=0 to find the x-intercept

  3x +0 = 6

  x = 6/3 = 2

Plot the intercepts and draw the line through them for the graph of this equation.

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Here, we have suggested graphing strategies that don't involve a lot of manipulation of the equations. The idea is to get there as quickly as possible with a minimum of mistakes.

8 0
3 years ago
The point at which a company's costs equal its revenues is the break-even point. C represents the cost, in dollars, of x units o
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Okay, so we know it is going to be more than 32000, right?

8 0
3 years ago
Can someone do my math homework for me? i will give you the information you need. My head hurts constantly and i get too distrac
Lera25 [3.4K]

Answer:

I'll do your Home work Just post the questions

3 0
3 years ago
Read 2 more answers
Line segment AB has endpoints A(1,8) and B(7,−4). What are the coordinates of the point located 5/6 of the way from A to B?
const2013 [10]

The coordinate of the point is (6,-2)

<h3>How to determine the coordinate of the point?</h3>

The given parameters are:

A = (1,8)

B = (7,-4)

The location of the point (i.e 5/6) means that the ratio is:

m :n = 5 : (6 - 5)

m : n = 5 : 1

The coordinate of the point is then calculated as:

(x,y) = \frac{1}{m + n}* (mx_2 + nx_1,my_2 + ny_1)

So, we have:

(x,y) = \frac{1}{5 + 1}* (5 * 7 + 1 * 1 , 5 * -4 + 1 * 8)

Evaluate

(x,y) = \frac{1}{6}* (36 , -12)

Evaluate the product

(x,y) = (6,-2)

Hence, the coordinate of the point is (6,-2)

Read more abut line segment ratio at:

brainly.com/question/12959377

#SPJ1

6 0
2 years ago
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