Transformations
(x-3)...: That means the graph shifted 3 units right.
...-1: that means the graph shifted 1 unit down.
answer: 3 units right, and 1 down
First solve the quadratic as you would an equation, so you will get two real zeroes p and q so that (x-p)(x-q)=0 is another way of expressing the quadratic. All quadratics can be represented graphically by a parabola, which could be inverted. When the x² coefficient is negative it’s inverted. If the coefficient of x² isn’t 1 or -1 divide the whole quadratic by the coefficient so that it takes the form x²+ax+b, where a and b are real fractions. The curve between the zeroes will be totally below the x axis for an upright parabola, and totally above for an inverted parabola. This fact is used for inequalities. An inequality will be <, ≤, > or ≥. This makes it easy to solve the inequality. If the position of the curve between the zeroes is below the axis then outside this interval it will be above, and vice versa. So we’ve defined three zones. x
q, and p
Answer:
(f o g)(4) = 45
Step-by-step explanation:
f(x)=4x+1
g(x)=x²-5
(f o g)(4)=?
(f o g)(4) = f(g(4))
Calculating g(4):
x=4→g(4)=4²-5
g(4)=16-5
g(4)=11
Replacing g(4)=11
(f o g)(4) = f(g(4))
(f o g)(4) = f(11)
Calculating f(11)
x=11→f(11)=4(11)+1
f(11)=44+1
f(11)=45
Replacing f(11)=45:
(f o g)(4) = f(11)
(f o g)(4) = 45
Answer:
Step-by-step explanation:
Negative numbers are "smaller" than positive numbers. Just arrange them.
