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3 years ago

________ is a method used to express extremely large or small numbers in a more practical method. Please watch your spelling.

Mathematics

2 answers:

Aleksandr [31]3 years ago

7 0

We would call it scientific notation

astraxan [27]3 years ago

6 0

The answer is scientific notation

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List of subsets of each set {1,3,5,7}

agasfer [191]

ANSWER

{},{1},{3},{5},{7},{1,3},{1,5},{1,7},{3,5},{3,7},{5,7},{1,3,5},{1,3,7},{3,5,7},{1,5,7},{1,3,5,7}

EXPLANATION

The given set is {1,3,5,7}.

This set has

${2}^{n} = {2}^{4} = 16$

subsets.

Where n=4 is the number of elements in the set.

Recall that the null set is a subset of every set and every set is a subset of itself.

The subsets are:

{}

{1},{3},{5},{7}

{1,3},{1,5},{1,7},{3,5},{3,7},{5,7}

{1,3,5},{1,3,7},{3,5,7},{1,5,7}

{1,3,5,7}

7 0

3 years ago

Cos (90-theta) • cosec90-theta) =tano. How?

denis-greek [22]

Answer:

______________________________________________________

TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-

For any right angled triangle with one angle α ,

$\cos (90 - \alpha ) = \sin \alpha$ or $\sin(90 - \alpha ) = \cos\alpha$

$cosec \: (90 - \alpha ) = \sec\alpha$ or $\sec(90 - \alpha ) = cosec\:\alpha$

SOME GENERAL TRIGNOMETRIC FORMULAS :-

$\sin \alpha = \frac{1}{cosec \: \alpha }$ or $cosec \: \alpha = \frac{1}{\sin \alpha }$

$\cos \alpha = \frac{1}{\sec \alpha }$ or $\sec \alpha = \frac{1}{\cos \alpha }$

______________________________________________________

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

$\cos (90 - \alpha ) \times cosec(90 - \alpha )$

$=> sin\alpha \times \sec\alpha$

$=> \sin\alpha \times \frac{1}{\cos\alpha }$

$=> \frac{\sin\alpha }{\cos\alpha }$

$=> \tan\alpha$ = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

3 0

3 years ago

Solve each equation you must use

n200080 [17]

1) The solution for m² - 5m - 14 = 0 are x=7 and x=-2.

2)The solution for b² - 4b + 4 = 0 is x=2.

Step-by-step explanation:

The general form of quadratic equation is ax²+bx+c = 0

where

a is the coefficient of x².
b is the coefficient of x.
c is the constant term.

To find the roots :

Sum of the roots = b
Product of the roots = c

1) The given quadratic equation is m² - 5m - 14 = 0.

From the above equation, it can be determined that b = -5 and c = -14

The roots are -7 and 2.

Sum of the roots = -7+2 = -5
Product of the roots = -7 $\times$ 2 = -14

The solution is given by (x-7) (x+2) = 0.

Therefore, the solutions are x=7 and x= -2.

2) The given quadratic equation is b² - 4b + 4 = 0.

From the above equation, it can be determined that b = -4 and c = 4

The roots are -2 and -2.

Sum of the roots = -2-2 = -4
Product of the roots = -2 $\times$ -2 = 4

The solution is given by (x-2) (x-2) = 0.

Therefore, the solution is x=2.

5 0

3 years ago

93 times 10 to the sixth power

Varvara68 [4.7K]

93 x 10^6 =
93 x 1,000,000 = 93,000,000

6 0

3 years ago

I bet you 10 points you will not answer this I think its B i need assurance

Flauer [41]

Answer:

(a) seems to be the closest to being correct of these five statements.

Step-by-step explanation:

Let's go through the list of possible descriptors:

a) There are no outliers. This seems to be the response most likely to be correct.

b) The distribution is not skewed left. It's skewed right.

c) The center is not 44. From what I see, the center is 48.

d) This distribution is not bimodal; it does not have two peaks.

d) The spread is not 38 to 67; it's 29 to 67.

5 0

3 years ago