All categories

2 years ago

________ is a method used to express extremely large or small numbers in a more practical method. Please watch your spelling.

Mathematics

2 answers:

Aleksandr [31]2 years ago

7 0

We would call it scientific notation

astraxan [27]2 years ago

6 0

The answer is scientific notation

You might be interested in

Simplify 2(x + y) + 3(x + y)

ANTONII [103]

The answer would be 5x+5y

5 0

3 years ago

What is just the coefficient of the 3rd term of (3x + 5y)^8 ?

Burka [1]

Answer:

i hope this is correct, i might be wrong(i am so sorry if i am wrong), but im thinking it is 8

Step-by-step explanation:

6 0

2 years ago

BRUH what is 14x(8-10)=6

bogdanovich [222]

Answer:

0.18

Step-by-step explanation:

14x(8-10)=6

Distribute 14x

112x-80x=6

32x=6

6/32=0.18

x=0.18

Hope this helps

........and is right :p

6 0

2 years ago

Use the discriminant to predict the nature of the solutions to the equation 4x-3x²=10. Then, solve the equation.

AleksandrR [38]

Answer:

Two imaginary solutions:

x₁= $\frac{2}{3} -\frac{1}{3} i\sqrt{26}$

x₂ = $\frac{2}{3} +\frac{1}{3} i\sqrt{26}$

Step-by-step explanation:

When we are given a quadratic equation of the form ax² +bx + c = 0, the discriminant is given by the formula b² - 4ac.

The discriminant gives us information on how the solutions of the equations will be.

If the discriminant is zero, the equation will have only one solution and it will be real
If the discriminant is greater than zero, then the equation will have two solutions and they both will be real.
If the discriminant is less than zero, then the equation will have two imaginary solutions (in the complex numbers)

So now we will work with the equation given: 4x - 3x² = 10

First we will order the terms to make it look like a quadratic equation ax²+bx + c = 0

So:

4x - 3x² = 10

-3x² + 4x - 10 = 0 will be our equation

with this information we have that a = -3 b = 4 c = -10

And we will find the discriminant: $b^{2} -4ac = 4^{2} -4(-3)(-10) = 16-120=-104$

Therefore our discriminant is less than zero and we know that our equation will have two solutions in the complex numbers.

To proceed to solve the equation we will use the general formula

x₁= (-b+√b²-4ac)/2a

so x₁ = $\frac{-4+\sqrt{-104} }{2(-3)} \\\frac{-4+\sqrt{-104} }{-6}\\\frac{-4+2\sqrt{-26} }{-6} \\\frac{-4+2i\sqrt{26} }{-6} \\\frac{2}{3} -\frac{1}{3} i\sqrt{26}$

The second solution x₂ = (-b-√b²-4ac)/2a

so x₂= $\frac{-4-\sqrt{-104} }{2(-3)} \\\frac{-4-\sqrt{-104} }{-6}\\\frac{-4-2\sqrt{-26} }{-6} \\\frac{-4-2i\sqrt{26} }{-6} \\\frac{2}{3} +\frac{1}{3} i\sqrt{26}$

These are our two solutions in the imaginary numbers.

7 0

2 years ago

Plz help with parent functions

grigory [225]

All positive numbers and zero. All positive numbers because any value that is absolute becomes positive.

7 0

2 years ago