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2 years ago

Andrea drew a regression line for this paired data set.

Mathematics

2 answers:

Tems11 [23]2 years ago

6 0

The equation of the line that passes through the points

(1,5) and (5,13) is y=2x+3

JulsSmile [24]2 years ago

6 0

Answer:

The correct option is 2.

Step-by-step explanation:

If a line passing through two points, then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

It is given that Andrea drew a regression line for this paired data set. Her line passed through (1, 5) and (5, 13) .

The equation of Andrea's regression line is

$y-5=\frac{13-5}{5-1}(x-1)$

$y-5=\frac{8}{4}(x-1)$

$y-5=2(x-1)$

$y-5=2x-2$

$y=2x-2+5$

$y=2x+3$

The equation of Andrea's regression line is y=2x+3. Therefore correct option is 2.

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An assembly line has two inspectors. The probability that the first inspector will miss a defective item is 0.06. If the defecti

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Answer:

probability that both passes a defective item is 0.8742‬

<h3>Step-by-step explanation:</h3>

probability that the first inspector misses is Pr( 1st misses)= 0.06

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3 years ago

Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?

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Step-by-step explanation:

$\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}$

$\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}$

$\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}$

$\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}$

Taking sin²θ common in both numerator & denominator, We get :

$\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{cot\theta = \dfrac{cos\theta}{sin\theta}}}}$

$\mathsf{\implies \dfrac{1 -cot^2\theta}{1 + cot^2\theta}}$

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$\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}$

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$\mathsf{\implies \dfrac{2}{3}}$

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