Answer:
Step-by-step explanation:
“the center of the ellipse is located below the given co-vertex”
Co-vertex and center are vertically aligned, so the ellipse is horizontal.
Equation for horizontal ellipse:
(x-h)²/a² + (y-k)²/b² = 1
with
a² ≥ b²
center (h,k)
vertices (h±a, k)
co-vertices (h, k±b)
foci (h±c,k), c² = a² -b²
One co-vertex is (-8,9), so h = -8.
One focus is (4,4), so k = 4.
Center (h,k) = (-8,4)
c = distance between center and focus = |-8 - 4| = 12
b = |9-k| = 5
a² = c² + b² = 169
(x+8)²/169 + (y-4)²/25 = 1
9 because a squre has equal sizes and area is leignth times width and 3 x 3= 9
Answer:
x/2.
Step-by-step explanation:
We replace the x in g(x) by f(x):
g(f(x)) = 1((x + 2/2) - 1
= (x + 2)/2 - 1
= (x + 2 - 2)/2
= x/2.
Answer: 414628192
Step-by-step explanation: ok, so take 5+5=10
10+ 6355334= 6355344 + 64= 6355408
then do 463454432/2 which = 231727216 then
646355408-231727216= 414628192
Have a good day (^_^)
