All categories

2 years ago

The can is 12cm high and 8cm diameter using the formula v=3r2h how much milk can the can hold answer in correct units

Mathematics

1 answer:

Tasya [4]2 years ago

7 0

R= radius which is 8/2 so 4 H= height which is 12 V= 3•4•2•12 V= 288

You might be interested in

I need help with number 3

sattari [20]

You multiply everything inside the brackets by what's outside it:

24-30x + 9
33 - 30x

D is the answer.

4 0

2 years ago

WHERE ARE THE EXPERTS AND ACE!!!!!!! I NEED HELP PLS SHARE YO SMARTNESS!!!!! WILL GIVE BRAINLIEST AND RATE AND VOTE!!! EASY IM J

Mazyrski [523]

Answer:

${ \bf{ \sec( \theta) = \frac{10}{6} }}$

Step-by-step explanation:

${ \boxed{ \bf{ \cos( \theta) = \frac{adjacent}{hypotenuse} }}}$

Adjacent = 6

Hypotenuse = 10

${ \sf{\sec( \theta) = \frac{1}{ \cos( \theta) } }}$

therefore:

${ \sf{ \sec( \theta) = \frac{hypotenuse}{adjacent} }} \\ \\ { \sf{ \sec( \theta) = \frac{10}{6} }}$

3 0

2 years ago

Find x. Find x. Find x. find x. find x. find x

joja [24]

Answer:

x = 5

Step-by-step explanation:

The sum of two interior angles in a triangle is equal to an exterior angle that's supplementary to the third interior angle

Therefore m<A + m<B = m<C

13x - 11 + 4x + 1 = 18x - 15 add like terms

17x - 10 = 18x - 15

15 - 10 = 18x - 17x

5 = x

8 0

3 years ago

Read 2 more answers

Which statement about the ordered pairs(-3, -3), (0,-3)and(3,-3) is not true?

Anuta_ua [19.1K]

The one that is wrong is. C. If all the x’s are different it is a function

4 0

3 years ago

Read 2 more answers

The roots of the quadratic equation $z^2 + az + b = 0$ are $2 - 3i$ and $2 + 3i$. What is $a+b$?

AlladinOne [14]

We know for our problem that the zeroes of our quadratic equation are $(2-3i)$ and $(2+3i)$ , which means that the solutions for our equation are $x=2-3i$ and $x=2+3i$ . We are going to use those solutions to express our quadratic equation in the form $a x^{2} +bx+c$ ; to do that we will use the zero factor property in reverse:
 $x=2-3i$
$x-2=-3i$
$x-2+3i=0$

 $x=2+3i$
$x-2=3i$
$x-2-3i=0$

Now, we can multiply the left sides of our equations:
 $(x-2+3i)(x-2-3i)= x^{2} -2x-3ix-2x+4+6i+3ix-6i-3^2i^2$
= $x^{2}-4x+4-9i^{2}$
= $x^{2} -4x+4+9$
= $x^{2} -4x+13$
Now that we have our quadratic in the form $a x^{2} +bx+c$ , we can infer that $a=1$ and $b=-4$ ; therefore, we can conclude that $a+b=1+(-4)=1-4=-3$ .

6 0

3 years ago