Given that a, b and c are positive integers, and abc=210, what is least possible sum for a+b+c
1 answer:
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6x^4-17x^3-7x^2+13x=3
6x^4-17x^3-7x^2+13x-3=3-3
6x^4-17x^3-7x^2+13x-3=0
y=6x^4-17x^3-7x^2+13x-3
y=0
The solutions are: x=-1, 1/2, 1/3 and 3
6x^4-17x^3-7x^2+13x-3=3-3
6x^4-17x^3-7x^2+13x-3=0
y=6x^4-17x^3-7x^2+13x-3
y=0
The solutions are: x=-1, 1/2, 1/3 and 3
Answer:
A= 75.06 Sq Cm
Step-by-step explanation:
Please refer to the picture attached with this.
In ΔABD
AB = 8.5 , AD = 6 and say BD = x
Applying Pythagoras theorem in this triangle
Pythagoras theorem says
where c is the side opposite to the right angle, and b and a are the other two sides of the right angled triangle.
Hence side
a = 6.02+19
a = 25.02
Now we apply the formula for area of a triangle which is given as
Where b is the base , here we have base as a = 25.02
h is the height , here h = 6
Putting these values in Formula we get
Hence Area of the triangle is 75.06 sq cm
