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weeeeeb [17]
3 years ago
5

Given that a, b and c are positive integers, and abc=210, what is least possible sum for a+b+c

Mathematics
1 answer:
Vesnalui [34]3 years ago
7 0

Answer:

The least possible sum for a+b+c is 18.

Step-by-step explanation:

As given a,b and c are positive integers and abc = 210

So, let us consider some situation in which the product abc = 20

  • If a, b and c are 5, 6 and 7 then

        abc = 210 & a+b+c = 18

  • If a, b and c are 3, 7 and 10 then

       abc = 210 & a+b+c = 20

  • If a, b and c are 7, 15 and 2 then

       abc = 24  & a+b+c = 24

  • If a, b and c are 2, 5 and 21 then

        abc = 210  & a+b+c = 28

From all of the above situation the least sum is 18 when a, b and c are 5, 6 and 7 respectively.

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and the area of a rectangle is just length * width.

\bf \textit{area of a rectangle}\\\\
A=length\cdot width\quad 
\begin{cases}
length=x\\
width=x\\
A=112
\end{cases}\implies 112=x\cdot x\implies 112=x^2
\\\\\\
\sqrt{112}=x\implies \sqrt{16\cdot 7}=x\implies \sqrt{4^2\cdot 7}=x\implies 4\sqrt{7}=x
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3 years ago
The graph represents the number of cups of flour for the number of cups of sugar ina cake recipe. Which ratio is accurate based
Dmitry_Shevchenko [17]
7.5
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7 0
3 years ago
Read 2 more answers
WILL MARK BRAINLIEST! PLEASE HELP!<br> Write 206 in base 7
Anna71 [15]

Answer:

413_7

Step-by-step explanation:

Convert the following to base 7:

206_10

Hint: | Starting with zero, raise 7 to increasingly larger integer powers until the result exceeds 206.

Determine the powers of 7 that will be used as the places of the digits in the base-7 representation of 206:

Power | \!\(\*SuperscriptBox[\(Base\), \(Power\)]\) | Place value

3 | 7^3 | 343

2 | 7^2 | 49

1 | 7^1 | 7

0 | 7^0 | 1

Hint: | The powers of 7 (in ascending order) are associated with the places from right to left.

Label each place of the base-7 representation of 206 with the appropriate power of 7:

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | __ | __ | )_(_7)

Hint: | Divide 206 by 7 and find the remainder. The remainder is the first digit from the right.

Determine the value of the first digit from the right of 206 in base 7:

206/7=29 with remainder 3

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | __ | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 29, by 7 and find the remainder. The remainder is the next digit.

Determine the value of the next digit from the right of 206 in base 7:

29/7=4 with remainder 1

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | 1 | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 4, by 7 and find the remainder. The remainder is the last digit.

Determine the value of the last remaining digit of 206 in base 7:

4/7=0 with remainder 4

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | 4 | 1 | 3 | )_(_7)

Hint: | Express 206_10 in base 7.

The number 206_10 is equivalent to 413_7 in base 7.

Answer: 206_10 =413_7

5 0
2 years ago
Their 15,000 kids in the multipurpose room.there is only 16 rows with 5 seats in each.how many kids will not have a seat to sit
sp2606 [1]

Answer: 14,920 kids

Step-by-step explanation:

15,000-(16×5)=x

15,000-80=x

14,920=x

8 0
3 years ago
Read 2 more answers
Helppppppppppppppppppp
Daniel [21]
Hey there! :D

Remember that the question said estimate. 

So 

47% rounds to 50% 

.5 and 1/2 are equal to 50% 

89 rounds to 90. 

You could say that:

1/2*90

0.5*90

90/2 

These will all work and will give you the same answer. 

I hope this helps!
~kaikers
8 0
3 years ago
Read 2 more answers
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