The probability that the first horse wins is 2/7. The probability that the second horse wins is 3/10. Since the events that the first horse wins and the second horse wins are shared exclusive, the probability that either the first horse or the second horse will win is :
2/7 + 3/10= 41/70
Hope this is correct.
The standard for is 2000+ 1200
361 + 173 =361+173
(a+b)+(a-b)=361+173
a+b=a-b=534
2a=534
a=267
267+b=361
b=94
the two numbers are 267 and 94
True I think I could be wrong gotta get these points
Answer:
Goodluck my dude.
Step-by-step explanation:
