Ask question

Ask question

All categories

3 years ago

13

The beginning of the week Joshua had $356 in a savings account at the end of the week he had only $123 in his savings account ri

ght and solve an equation to find amount of money that goes with being during the week

1 answer:

zavuch27 [327]3 years ago

5 0

Answer:

$233

Step-by-step explanation:

$ 356 - $ 123=$ 233

it's basically simple subtracting

You might be interested in

Does anyone know what 1/2*1/2*1/2*1/2 equals? <br> answers:<br> 4/48<br> 5/16<br> 1/20736<br> 4/12

dedylja [7]

I believe it would be 1/16.

3 0

3 years ago

Read 2 more answers

The function h(t) = −5t2 + 20t shown in the graph models the curvature of a satellite dish: graph of parabola starting at zero c

ipn [44]

Answer:

Part 1) Option B: 0 ≤ x ≤ 4

Part 2) Option C: (5x − 1)(2x − 3)

Part 3) Option C: The crop yield decreased by 10 pounds per acre from year 10 to year 20.

Part 4) Option B: f(x) = (2x + 1)(2x − 1)

Part 5) Option A: The company earned 85 billion dollars in 2008

Part 6) Option C: (3, 0) and (5, 0)

Step-by-step explanation:

Part 1) we have

$h(t)=-5t^{2}+20t$

This is a vertical parabola open downward

The vertex is a maximum

The x-intercepts are the points (0,0) and (4,0)

The vertex is the point (2,20) ---> The x-coordinate of the vertex is the midpoint of the x-intercepts

so

The domain is the interval ----> [0,4]

$0\leq t\leq 4$

The range is the interval ----> [0,20]

$0\leq h(t)\leq 20$

Part 2) we have

$V=10x^{2} -17x+13$

where

x is the time in minutes

V is the volume in gallons

we know that

When the trough is empty, the volume is equal to zero

so

For V=0

$10x^{2} -17x+3=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$10x^{2} -17x+3=0$

so

$a=10\\b=-17\\c=3$

substitute in the formula

$x=\frac{-(-17)(+/-)\sqrt{-17^{2}-4(10)(3)}} {2(10)}$

$x=\frac{17(+/-)\sqrt{169}} {20}$

$x=\frac{17(+/-)13} {20}$

$x=\frac{17(+)13} {20}=\frac{3}{2}$

$x=\frac{17(-)13} {20}=\frac{1}{5}$

so

$10x^{2} -17x+3=10(x-\frac{3}{2})(x-\frac{1}{5})$

simplify

$10(x-\frac{3}{2})(x-\frac{1}{5})=(2x-3)(5x-1)$

Part 3) we have

$f(x)=-x^{2}+20x+100$

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

the average rate of change is equal to

$\frac{f(b)-f(a)}{b-a}$

In this problem we have

$f(a)=f(10)=-(10)^{2}+20(10)+100=200$

$f(b)=f(20)=-(20)^{2}+20(20)+100=100$

$a=10$

$b=20$

Substitute

$\frac{100-200}{20-10}$

$-\frac{100}{10}=-10$ ----> is a decreasing function

therefore

The crop yield decreased by 10 pounds per acre from year 10 to year 20.

Part 4) we have

$f(x)=4x^{2} -1$

<em>Find out the x-intercepts</em>

Remember that the x-intercepts are the values of x when the value of the function is equal to zero

so

For f(x)=0

$4x^{2} -1=0$

Solve for x

$4x^{2}=1$

$x^{2}=\frac{1}{4}$

take square root both sides

$x=(+/-)\frac{1}{2}$

so

$f(x)=4x^{2} -1=4(x-\frac{1}{2})(x+\frac{1}{2})=(2x-1)(2x+1)$

Part 5) we have

$t^{2}+14t+85$

Remember that

The y-intercept of a function is the value of the function (output value) when the value of x (input value) is equal to zero

In this problem

The expression represent a company's net sales, in billions, from 2008 to 2018

t is the number of years since the end of 2008

so

For t=0 -----> represent the end of 2008

$(0)^{2}+14(0)+85=85\ billion\ dollars$

therefore

The company earned 85 billion dollars in 2008.

Part 6) What are the x-intercepts of the parabola?

we have the points (2,3),(4,-1),(6,3)

This is a vertical parabola open upward

The vertex represent a minimum

In this problem the vertex is the point (4,-1)

The equation of a vertical parabola in vertex form is equal to

$y=a(x-h)^2+k$

where

a is a coefficient

(h,k) is the vertex

we have

(h,k)=(4,-1)

substitute

$y=a(x-4)^2-1$

take the point (2,3) and substitute in the quadratic equation to solve for a

For x=2, y=3

$3=a(2-4)^2-1$

$3=4a-1$

$4a=4$

$a=1$

The quadratic equation is

$y=(x-4)^2-1$

Find out the x-intercepts

Remember that the x-intercepts are the values of x when the value of the function is equal to zero

so

For y=0

$(x-4)^2-1=0$

Solve for x

$(x-4)^2=1$

take square root both sides

$(x-4)=(+/-)1$

$x=4(+/-)1$

$x=4+1=5\\x=4-1=3$

therefore

The x-intercepts are the points (3,0) and (5,0)

7 0

3 years ago

Read 2 more answers

Violet is baking a mixed berry pie that contains blueberries, cherries, blackberries, and raspberries. She uses three times as m

erastova [34]

Answer:

Blackberries= 30

Rasberries=30

Blueberries=60

Step-by-step explanation:

10 x 3 = 30 blackberries

Black berries is the same amount as rasberries

30 x 2= 60 blueberries

7 0

3 years ago

Read 2 more answers

A 4. 9-mm-wide swimming pool is filled to the top. The bottom of the pool becomes completely shaded in the afternoon when the su

cestrela7 [59]

The depth of the swimming pool that is filled to the top is; 4 m

<h3>Snell's Law</h3>

I have attached a schematic diagram showing this question.

The correct width of the pool is 4 meters. Thus; w = 4 m

Incident Angle; θ₁ = 20°

A right angle is 90° and so the angle θ₂ is calculated from;

θ₂ = 90° - θ₁

θ₂ = 90° - 20°

θ₂ = 70°

We can use snell's law formula to find θ₃.

Thus;

n₁sinθ₂ = n₂sinθ₃

where;

n₁ is refractive index of air = 1

n₂ is refractive index of water = 1.33

Thus;

1*sin 70 = 1.33*sin θ₃

sin θ₃ = (sin 70)/1.33

Solving this gives;

θ₃ = 44.95°

By usage of trigonometric ratios we can find the depth of the pool using;

w/d = tan θ₃

Thus;

d = w/(tan θ₃)

d = 4/(tan 44.95)

d ≈ 4 m

Read more about Snell's Law at; brainly.com/question/10112549

6 0

2 years ago

Helppppppppppppp plssssssssssss

beks73 [17]

area is found by multiplying length by width

so

26.4 times 12.25 =

and the answer is feet squared

8 0

3 years ago