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s2008m [1.1K]
3 years ago
8

What is the area of the triangle? (Pls help thx)

Mathematics
1 answer:
Anna [14]3 years ago
5 0
To solve for the area of the triangle 
Use the formula 1/2(base *height)
1/2 * 17* 4
68/2
34

I believe the area of the triangle is therefore 34ft
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Solve the system of linear equations.<br> 2x - 3y = 18
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Answer:

x = (18 + 3y)/2 y = (18 - 2x)/3

Step-by-step explanation:

For whichever variable you want to solve for, isolate it on one side. For example, if you want to solve for x, first add 3y to each side.

2x = 18 + 3y

Then, divide everything by two.

x = (18 + 3y)/2

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y= -2 and x= 2.

Step-by-step explanation:

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Dominik [7]

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Itis divisible by 2,3,4,6 and 11

Step-by-step explanation:


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3 years ago
Prove that cos 3x= cosx (2 cos 2x-1)​
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Step-by-step explanation:

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<em>Note :</em>

<u>T</u><u>he sum and difference of two angles :</u>

\begin{aligned}\sin\left(\alpha\pm\beta\right)&=\sin\alpha\cdot\cos\beta\pm\cos\alpha\cdot\sin\beta\\\cos\left(\alpha\pm\beta\right)&=\cos\alpha\cdot\cos\beta\mp\sin\alpha\cdot\sin\beta\\\tan\left(\alpha\pm\beta\right)&=\frac{\tan\alpha\pm\tan\beta}{1\mp\tan\alpha\cdot\tan\beta}\end{aligned}

<u>Double </u><u>angle </u><u>:</u>

\begin{aligned}\sin 2\alpha&=2\cdot\sin\alpha\cdot\cos\alpha\\\cos 2\alpha&=\cos^2 \alpha-\sin^2\alpha\\&=2\cdot\cos^2 \alpha-1\\&=1-2\cdot\sin^2 \alpha\\\tan 2\alpha&=\frac{2\cdot\tan\alpha}{1-\tan^2 \alpha}\end{aligned}

8 0
3 years ago
ANOTHER free 50 points to u cuties, First to answer 3+3=? (another hard question :P) gets brainliest (if itll let me this time)
kakasveta [241]

Answer:

Step-by-step explanation:

Hi

7 0
4 years ago
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