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Vsevolod [243]
2 years ago
12

Find the l.c.m of x²+x, x²-1, x²-x​

Mathematics
1 answer:
olga2289 [7]2 years ago
6 0

Answer:

X³-x

Step-by-step explanation:

Lcm

x(x-1)(x+1)

x(x²-1)

x³-x

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Alexa is going to a carnival that has games and rides. Each game costs $3 and each ride costs $4. Alexa spent $54 altogether on
tia_tia [17]
Game =$6 and ride=$9, to solve is 3x+4y=54
x+y=15
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3 years ago
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Which statements are true about the regular polygon? Select three options. The sum of the measures of the interior angles is 900
Akimi4 [234]

Answer:

The sum of the measures of the interior angles is 900° is False

Each interior angle measures 108° is True

All of the angles are congruent is True

The polygon is a regular hexagon is False

The sum of the measures of the interior angles is 180(5 – 2)° is True

Step-by-step explanation:

A pentagon is a polygon having five sides and equal angles. We can find the sum of the measures of the interior angles through 180*(n-2) where n = 5(number of sides a polygon has)

180*(5-2)= 180(3)=540°

Now the angles are 540/5 = 108°

This shows that the statement:

The sum of the measures of the interior angles is 900° is False

Each interior angle measures 108° is True

All of the angles are congruent is True

The polygon is a regular hexagon is False

The sum of the measures of the interior angles is 180(5 – 2)° is True ....

3 0
3 years ago
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Find the standard form of the equation of the parabola with a focus at (5, 0) and a directrix at x = -5.
Elena-2011 [213]
Let's notice, the focus is at (5,0) and the directrix at x = -5.

keep in mind that there's a distance "p" from the vertex to either of those fellows, therefore, if the focus is at 5,0 and the directrix x = -5, the vertex is half-way between them, check the picture below.

notice the distance "p" there, now, is a horizontal parabola, opening to the right, meaning the value for "p" is positive, or just 5, thus

\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
\boxed{(y-{{ k}})^2=4{{ p}}(x-{{ h}})}
\\\\
(x-{{ h}})^2=4{{ p}}(y-{{ k}})
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
h=0\\
k=0\\
p=5
\end{cases}\implies (y-0)^2=4(5)(x-0)\implies y^2=20x
\\\\\\
\cfrac{y^2}{20}=x\implies \cfrac{1}{20}y^2=x

8 0
3 years ago
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Answer:

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7 0
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Answer:

Answer is 1715

Step-by-step explanation:

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