I read this as -5e⁻⁴ˣ⁺²+3=½log₁₀(x²+1).
If this is not right the steps below can guide you to a possible solution when the correct formula is used.
My calculator is a Casio fx-85GT PLUS which has a function facility (MODE 3: TABLE).
I input the function: -5e⁻⁴ˣ⁺²+3-½log₁₀(x²+1). I assumed that log was log to base 10 rather than natural log ln.
The facility asks me to input a start value, end value and step value. I chose -10, 10 and 1 initially.
After a few seconds of evaluating a table of results the calculator showed me the results of plugging in x=-10 up to 10 in steps of 1.
The results showed the evaluation for each of the 21 values and I looked for the sign of the result to change.
For x=0 the result was -33.95 approx and for x=1 it was 2.1728 approx. So between 0 and 1 there is a zero, a solution for x.
I returned to the function and changed the parameters to start=0, end=1, step=0.1 to begin the next evaluation.
This time the sign change occurred between x=0.6 and 0.7.
I returned to the function with parameters: start=0.6, end=0.7, step=0.01.
The sign change occurred between 0.63 and 0.64, the start and end parameters with step=0.001 for the next iteration.
The solution is between 0.633 and 0.634.
Repeat the process one more time with step=0.0001. The sign change was between 0.6338 and 0.6339 so the solution to three dec places is 0.634.
Answer:
0.231
Step-by-step explanation:
Let the Probability of students that knew the correct answer be: P(A)
P(A) = 60% = 0.6
Let the Probability that the student picked the wrong answer even if he/she knows the right answer be: P(B)
P(B) = 15% =0.15
Let the Probability of the student that do not knew the correct answer Be P(C)
P(C) = 1 - P(A)
P(C) = 1 - 0.6
P(C) = 0.4
Let the Probability that the student does not know the right answer but guessed it correctly be: P(D)
P(D) = 25% = 0.25
Let the Probability that the student picked the right answer even if he/she knows the right answer be: P(E)
P(E) = 1 - P(B)
P(E) = 1 - 0.15
P(E) = 0.85
Probability that the student got the answer wrong = (0.60 X 0.15) + (0.40 X 0.75) = 0.39
P( Student knew answer given he answered wrong) = 
=
=
= 0.23076923077
= 0.231
The area of the surface of the pool is 7322.64 m².
<h3>What is Area of rectangle?</h3>
The area of rectangle is product of length and its breadth.
i.e., length * breadth
Given: Length = 100 m, Width = 52 m and Diameter = 52 m
Area of rectangle,
= 100 × 52
= 5200 m²
Now,
Area of semicircle = 1/2 × πr²
=1/2 × 3.14 × 26²
= 1061.32 m²
Hence, area of the surface of the pool is
= 1061.32 + 1061.32 + 5200
= 7322.64 m²
Learn more about this concept here:
brainly.com/question/15461609
#SPJ1
The answer is going to be yes it's rational. hope that helped
