Answer:
f(x) and g(x) are inverses
Step-by-step explanation:
* Lets check the inverse function
- If f(x) = y has a domain = x and a range = y, then f^-1 is the
inverse of f with a domain = y and a range = x
- f(x) = f^-1(x) = x
* Now lets solve the problem
∵ f(x) = 8/x
∵ g(x) = 8/x
∴ fg(x) = f(8/x)
∴ fg(x) = 8/(8/x) = 8 ÷ 8/x ⇒ change division sign to the multiplication
sign and reciprocal the fraction after the division sign
∴ fg(x) = 8 × x/8 = x
* Now lets find gf(x)
∴ gf(x) = g(8/x)
∴ gf(x) = 8/(8/x) = 8 ÷ 8/x
∴ gf(x) = 8 × x/8 = x
∵ f(x) = f^-1(x) = x
* fg(x) = gf(x) = x
∴ f(x) and g(x) are inverses
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Answer:
the answer is -1 its 1 Because you divide
has critical points where the derivative is 0:
The second derivative is
and 
, which indicates a local minimum at 
with a value of 
.
At the endpoints of [-2, 2], we have 
and 
, so that has an absolute minimum of 
and an absolute maximum of 
on [-2, 2].
So we have
