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3 years ago

PLEASE HELP WILL MARK BRAINIEST -see attachment-

Mathematics

1 answer:

TiliK225 [7]3 years ago

4 0

Answer:

f(x) and g(x) are inverses

Step-by-step explanation:

* Lets check the inverse function

- If f(x) = y has a domain = x and a range = y, then f^-1 is the

inverse of f with a domain = y and a range = x

- f(x) = f^-1(x) = x

* Now lets solve the problem

∵ f(x) = 8/x

∵ g(x) = 8/x

∴ fg(x) = f(8/x)

∴ fg(x) = 8/(8/x) = 8 ÷ 8/x ⇒ change division sign to the multiplication

sign and reciprocal the fraction after the division sign

∴ fg(x) = 8 × x/8 = x

* Now lets find gf(x)

∴ gf(x) = g(8/x)

∴ gf(x) = 8/(8/x) = 8 ÷ 8/x

∴ gf(x) = 8 × x/8 = x

∵ f(x) = f^-1(x) = x

* fg(x) = gf(x) = x

∴ f(x) and g(x) are inverses

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Solve 7x – 2y = –3 14x + y = 14 a. (4,5/7) b. (4,7/5) c. (5/7,4) d. (7/5,4)

den301095 [7]

7x - 2y = -3 . . . (1)
14x + y = 14 . . . (2)
(1) x 2 => 14x - 4y = -6 . . . (3)
(2) - (3) => 5y = 20
y = 20/5 = 4
From (1); 7x - 2(4) = -3
7x - 8 = -3
7x = -3 + 8 = 5
x = 5/7

Solution = (5/7, 4)

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4 years ago

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I really need help with 7 and 8

Nikolay [14]

7. 55 + 35 + x = 180 x = 90 making the triangle a right triangle.

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3 years ago

What is the area of the triangle? 8 4 5

Tpy6a [65]

Answer:

Step-by-step explanation:

1/2 (perpendicular height × base)

1/2(4×8)

2×8

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3 years ago

Solve system of equations

kotykmax [81]

1.) x= 3

2.) y= -1

3.) z= negative 4/3

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3 years ago

(3xy/3x^2-12)*(x^2+3x+2/xy+y)

TiliK225 [7]

Value of expression $(3xy/3x^2-12)*(x^2+3x+2/xy+y)$ is $\frac{x}{x-2}$ .

Step-by-step explanation:

Here we need to evaluate expression : (3xy/3x^2-12)*(x^2+3x+2/xy+y) or ,

$(3xy/3x^2-12)*(x^2+3x+2/xy+y)$

Let's simplify this

⇒ $(\frac{3xy}{3x^2-12})(\frac{x^2+3x+2}{xy+y})$

Factorizing the terms we get:

⇒ $(\frac{3xy}{3(x^2-4)})(\frac{x^2+2x+x+2}{y(x+1)})$ { $a^2-b^2=(a+b)(a-b)$ }

⇒ $(\frac{xy}{(x-2)(x+2)})(\frac{x(x+2)+1(x+2)}{y(x+1)})$

⇒ $(\frac{xy}{(x-2)(x+2)})(\frac{(x+1)(x+2)}{y(x+1)})$

Cancelling similar terms we get:

⇒ $\frac{x}{x-2}$

Therefore , Value of expression $(3xy/3x^2-12)*(x^2+3x+2/xy+y)$ is $\frac{x}{x-2}$ .

3 0

3 years ago

PLEASE HELP WILL MARK BRAINIEST​ -see attachment-

PLEASE HELP WILL MARK BRAINIEST -see attachment-