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Sholpan [36]
2 years ago
9

Right now there are 600 everlasting roses in my garden. I want at least 200 roses in the garden at all times. If the gardener cu

tting 25 roses a week to decrote my throne room, how many more will i be able to have AT LEAST 200 roses in my garden

Mathematics
2 answers:
Radda [10]2 years ago
8 0

Answer:

Thefore, we conclude that she can have another 16 weeks, more than 200 roses.

Step-by-step explanation:

We know that right now there are 600 everlasting roses in garden. I want at least 200 roses in the garden at all times. If the gardener cutting 25 roses  a week to decrote my throne room.

We calculate:

t=(600-200) : 25\\\\t=400 : 25\\\\t=16\\

Thefore, we conclude that she can have another 16 weeks, more than 200 roses.

Darya [45]2 years ago
7 0

Step-by-step explanation:

Below is an attachment containing the solution.

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Which form of a quadratic function is easiest to use when finding the maximum or minimum value of the function?
alexandr402 [8]

Answer:

ax² + bx + c

Step-by-step explanation:

The form of a quadratic equation that is easy to use when finding the maximum or minimum value of the function is ax² + bx + c.

Suppose a quadratic function:

f(x) = 2x² - 8x + 9

Use ( -b/2a ,  f(-b/2a) ).

-b/2a

a = 2

b = -8

-(-8)/2(2)

8/4

= 2

f(2) = 2(2)² - 8(2) + 9

f(2) = 2(4) - 8(2) + 9

f(2) = 8 - 16 + 9

f(2) = 1

The minimum value of this quadratic function is (2, 1).

It represents a minimum value because a > 0.

4 0
3 years ago
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What is the slope of the line shown?
earnstyle [38]

Answer:

The slope is 45.

Step-by-step explanation:

Using the slope formula by two points:

m=(y2-y1)/(x2-x1)

m=(210-120)/(4-2)

m=45

7 0
2 years ago
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When the velocity v of an object is very​ large, the magnitude of the force due to air resistance is proportional to v squared w
Sati [7]

Answer:

Step-by-step explanation:

The model fo the shell is given by the following equation of equilibrium:

\Sigma F = -b\cdot v^{2} - m\cdot g = m\cdot \frac{dv}{dt}

This first-order differential equation has separable variables, which are cleared herein:

\int\limits^t_{0\,s} \, dt = -\frac{m}{b} \int\limits^{0\,\frac{m}{s} }_{600\,\frac{m}{s} } {\frac{1}{ v^{2}+\frac{m}{b}\cdot g } } \, dv

The solution of this integral is:

t = -\frac{m}{2b}\cdot \left[\tan^{-1} \left(\frac{v}{\sqrt{\frac{m\cdot g}{b} } }\right) - \tan^{-1} \left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } }\right)\right]

\tan^{-1} \left(\frac{v}{\sqrt{\frac{m\cdot g}{b} } }  \right)=-\frac{2\cdot b\cdot t}{m} + \tan^{-1}\left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } }  \right)

\frac{v}{\sqrt{\frac{m\cdot g}{b} } }=\tan \left[-\frac{2\cdot b\cdot t}{m} + \tan^{-1}\left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } }  \right)\right]

v = \sqrt{\frac{m\cdot g}{b} } \left [\frac{\tan \left(-\frac{2\cdot b \cdot t}{m}  \right)+ \left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } }  \right)}{1 - \left(\frac{600}{\sqrt{\frac{m\cdot g}{b} } }  \right)\cdot \tan \left(-\frac{2\cdot b \cdot t}{m}  \right) }\right]

4 0
3 years ago
The equation of line m is 3x−5y=−4.
a_sh-v [17]
I line that is perpendicular is a line with reversed slopes like 2/1 is perpendicular to -1/2. So find the slope by getting the y by itself and reverse it. Remember to switch the signs too! P.S. if you don't know how to get the y by itself just take and subtract 3x from -5y and -4 then divide by 5. Hope I helped!
8 0
2 years ago
Y2 -(-5y?) = ???????
borishaifa [10]
The answer to your question would be y2 +5y.
3 0
3 years ago
Read 2 more answers
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