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Mrac [35]
3 years ago
12

Do the following side lengths form a right triangle? Explain. 18 ft, 23 ft, 29 ft

Mathematics
1 answer:
bekas [8.4K]3 years ago
4 0

Answer:

Explaination:

Step-by-step explanation:

B: yes; 18^2 + 29^2=1165(equal sign with slash) 23^2

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What is the row echelon form of this matrix?
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The row echelon form of the matrix is presented as follows;

\begin{bmatrix}1 &-2  &-5  \\ 0& 1 &  -7\\ 0&0  &1  \\\end{bmatrix}

<h3>What is the row echelon form of a matrix?</h3>

The row echelon form of a matrix has the rows consisting entirely of zeros at the bottom, and the first entry of a row that is not entirely zero is a one.

The given matrix is presented as follows;

\begin{bmatrix}-3 &6  &15  \\ 2& -6 &  4\\ 1&0  &-1  \\\end{bmatrix}

The conditions of a matrix in the row echelon form are as follows;

  1. There are row having nonzero entries above the zero rows.
  2. The first nonzero entry in a nonzero row is a one.
  3. The location of the leading one in a nonzero row is to the left of the leading one in the next lower rows.

Dividing Row 1 by -3 gives:

\begin{bmatrix}1 &-2  &-5  \\ 2& -6 &  4\\ 1&0  &-1  \\\end{bmatrix}

Multiplying Row 1 by 2 and subtracting the result from Row 2 gives;

\begin{bmatrix}1 &-2  &-5  \\ 0& -2 &  14\\ 1&0  &-1  \\\end{bmatrix}

Subtracting Row 1 from Row 3 gives;

\begin{bmatrix}1 &-2  &-5  \\ 0& -2 &  14\\ 0&2  &4  \\\end{bmatrix}

Adding Row 2 to Row 3 gives;

\begin{bmatrix}1 &-2  &-5  \\ 0& -2 &  14\\ 0&0  &18  \\\end{bmatrix}

Dividing Row 2 by -2, and Row 3 by 18 gives;

\begin{bmatrix}1 &-2  &-5  \\ 0& 1 &  -7\\ 0&0  &1  \\\end{bmatrix}

The above matrix is in the row echelon form

Learn more about the row echelon form here:

brainly.com/question/14721322

#SPJ1

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The trapezoid has two parallel sides
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The graph shows the favorite colors chosen by some middle school students. Which statement is supported by the information in th
Karolina [17]

Answer:

Um you didnt attach a file or anything make one again and ill answer it just attach a screenshot of the problem

Step-by-step explanation:

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Type the correct answer in the box. Round off your answer to the nearest integer.
Ugo [173]

Answer:

59°

Step-by-step explanation:

In triangle DAB, by Pythagoras theorem:

DB= \sqrt {6^2 +5^2} =\sqrt{36+25}=\sqrt{61}

Next, in triangle DCB, by Pythagoras theorem:

DB= \sqrt {(\sqrt {61} )^2 - 4^2} =\sqrt{61-16}=\sqrt{45}

Now, by sin rule.

\frac{ \sin \: p}{ \sqrt{45} }  =  \frac{ \sin 90 \degree}{ \sqrt{61} }  \\  \\ \frac{ \sin \: p}{ 6.70820393}  =  \frac{ 1}{ 7.81024968 }  \\  \\ \sin \: p =  \frac{ 6.70820393}{7.81024968}  \\  \\ \sin \: p = 0.858897501 \\  \\p = 59.19301883 \degree \\  \\ p  \approx 59 \degree

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