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Mrac [35]
3 years ago
12

Do the following side lengths form a right triangle? Explain. 18 ft, 23 ft, 29 ft

Mathematics
1 answer:
bekas [8.4K]3 years ago
4 0

Answer:

Explaination:

Step-by-step explanation:

B: yes; 18^2 + 29^2=1165(equal sign with slash) 23^2

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PLEASE HELP!! SHOW WORK! &lt;3<br> Find the area of this figure. Dimensions are in meters.
densk [106]

Answer:

  2√46 + 25π/4 ≈ 33.2 . . . . m²

Step-by-step explanation:

The altitude of the triangle is given by the Pythagorean theorem. The right triangle of interest is the one that has 5√2 as its hypotenuse, and a leg of half the base shown. Then the other leg, the altitude of the triangle, is ...

  h = √((5√2)² - 2²) = √46

Then the area of the triangle shown is ...

  A = (1/2)bh = (1/2)(4)(√46)

  A = 2√46

__

The area of the semicircle is given by the formula ...

  A = (1/2)πr²

Filling in the radius shown, the area is computed as ...

  A = (1/2)π(5√2/2)² = 25π/4

So, the total area of the figure is ...

  total area = triangle area + semicircle area

  = 2√46 + 25π/4 . . . square meters

  ≈ 33.2 . . . square meters

3 0
3 years ago
A student spent 15 minutes getting a 2-foot by 3-foot bulletin board. To the nearest tenth of a minute, how long did it take the
Cerrena [4.2K]

Answer:

The student took 2.5 minutes to paint 1 square foot.

Step-by-step explanation:

In order to know how long the student took to paint each square foot we first need to know the total area of the bulletin board. Since it is a rectangle we can compute it's area by multiplying the width and the height. That is:

area = 2*3 = 6 square foot

Since the student took 15 minutes to paint the whole board the pace at which he was working can be calculated by dividing the total area of the board by the time he took to paint all of it. So we have:

pace = 6/15 = 0.4 foot/min

To find how long it took him to paint 1 square foot we can divide it by the pace he was painting. We have:

time = 1/0.4 = 2.5 minutes

The student took 2.5 minutes to paint 1 square foot.

3 0
3 years ago
Can someone please help me with this question i have 3 minutes left
kicyunya [14]

Answer:

It will cost 11 cents a day.

Step-by-step explanation:

1.98/18=11

plzz have brainiest

8 0
2 years ago
Find the second derivative y= x^2lnx
Dimas [21]
First we use product rule
y=x^2lnx
dy/dx = x^2 d/dx (lnx) + lnx d/dx (x^2)
dy/dx = x^2 (1/x) + lnx (2x)
dy/dx = x + 2xlnx

now taking second derivative:
d2y/dx2 = 1 + 2[x (1/x) + lnx (1)]
d2y/dx2 = 1 + 2[1+lnx]
         1+2+2lnx
         3+2lnx is the answer


3 0
3 years ago
How can you solve problems involving direct variation?
never [62]

Answer:

Solving a Direct Variation Problem

Write the variation equation: y = kx or k = y/x.

Substitute in for the given values and find the value of k.

Rewrite the variation equation: y = kx with the known value of k.

Substitute the remaining values and find the unknown.

Step-by-step explanation:

8 0
3 years ago
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