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Marat540 [252]
4 years ago
9

Rationalize the numerator or denominator and simplify URGENT!!! What did I do wrong??

Mathematics
1 answer:
iragen [17]4 years ago
7 0
Oof idkkkkkkk ..........lol
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ULTICULO
yaroslaw [1]

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Step-by-step explanation:

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3 years ago
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2/9 divided by 6/27 fill the box with a fraction that makes the equation true
Strike441 [17]

Answer:

1

Step-by-step explanation:

2 /9÷   6/ 27=1

6 0
3 years ago
Pls help! Be honest pls be honest......
barxatty [35]

Answer:

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Step-by-step explanation: its where the dots are or are u doing an equation?

3 0
3 years ago
-(12x-6)=12x 6 solve for x
postnew [5]
6=24x
hope this helped :)
tell me if u need anymore help
5 0
4 years ago
In a bag of m&m's there are 5 brown 6 yellow 4 blue 3 green and 2 orange. What's the probability of getting 3 yellow m&m
olasank [31]
There are 5+6+4+3+2=20 m&m's in the bag.
Calculate in how many ways you can choose 3 m&m's from 20:
_{20} C _3=\frac{20!}{3!(20-3)!}=\frac{20!}{3! \times 17!}=\frac{17! \times 18 \times 19 \times 20}{6 \times 17!}=\frac{18 \times 19 \times 20}{6}=3 \times 19 \times 20= \\
=1140

There are 6 yellow m&m's.
Calculate in how many ways you can choose 3 m&m's from 6:
_6 C _3 = \frac{6!}{3!(6-3)!}=\frac{6!}{3! \times 3!}=\frac{3! \times 4 \times 5 \times 6}{3! \times 6}=\frac{4 \times 5 \times 6}{6}=4 \times 5=20

The probability is the number of ways of choosing 3 m&m's from 6 m&m's divided by the number of ways of choosing 3 m&m's from 20 m&m's.
P=
\frac{20}{1140}=\frac{20 \div 20}{1140 \div 20}=\frac{1}{57}

The probability is 1/57.
4 0
3 years ago
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