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dimaraw [331]
3 years ago
9

Look at this graph:

Mathematics
2 answers:
Ray Of Light [21]3 years ago
7 0
You could try using photo math
Norma-Jean [14]3 years ago
3 0

Answer:

2/3

Step-by-step explanation:

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Ur going to see me a lot today
zimovet [89]

Answer:

16

Step-by-step explanation:

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3 years ago
PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU B
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Answer:

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Step-by-step explanation:

6 0
3 years ago
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Mary is an years old. What expression represents her age 7 years from now? Two years ago?
Rudiy27

Answer

What expression represents her age 7 years from now?

y =x+7x

Two years ago?

z=y-2x

Step-by-step explanation:

7 0
3 years ago
a small rocket is shot from the edge of a cliff suppose that after t seconds the rocket is y meters above the cliff where y=30t-
Natalka [10]

Answer:

Greatest height: 45 meters

Time for greatest height: 3 seconds

Height after 5 seconds: 25 meters above the cliff

Time for height of 40 meters: 7.123 seconds

Height after 7 seconds: -35 meters (35 meters below the cliff)

Step-by-step explanation:

to find the maximum height, we need to calculate the derivative of y in relation to t and then find when dy/dt = 0:

dy/dt = 30 - 10t = 0

10t = 30

t = 3 seconds

In this time, the height is:

y = 30*3 - 5*3^2 = 45 meters

After 5 seconds, the height is:

y = 30*5 - 5*5^2 = 25 meters

The time for the height of 40 meters is:

40 = 30t - 5t^2

t^2 - 6t - 8 = 0

Using Bhaskara's formula, we have:

Delta = 6^2 + 4*8 = 68

sqrt(Delta) = 8.246

t1 = (6 + 8.246) / 2 = 7.123 seconds

t2 = (6 - 8.246) / 2 = -1.123 seconds (negative value for time is not valid)

So the time when the rocket reaches 40 meters is 7.123 seconds

After 7 seconds, the height is:

y = 30*7 - 5*7^2 = -35 meters

The rocket will be 35 meters below the cliff.

5 0
3 years ago
How to work problem out<br> -8s + 1 = 33
dezoksy [38]
First you subtract 1 from 33 then you will get 32. After divide by 8. S= 4
6 0
3 years ago
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