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Lyrx [107]
3 years ago
6

Rob is making lemonade. He uses 8 lemons to make 4 quarts of lemonade.

Mathematics
1 answer:
ki77a [65]3 years ago
4 0

Answer:

I believe that would be 2 lemons for one quart.

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For the function y = 3x^2 - 12x + 4, what is the mirror point for the y-intercept? Give your answer in (x,y) point form.
saveliy_v [14]

Answer:

Your in Pacyber aren't you? Mr. Breux class? Anyway the answer is (0,-4)

Step-by-step explanation:

The y intercept is (0,-4)

6 0
3 years ago
John bought a new home in 2002. The value of the home increases 4% each year. If the price of the house is $375,000 in 2020, how
skad [1K]
Using the formula of P(1 + r)^n = x where p represents the initial value, r represents the rate and n represents the number of years and x is our final output. We want to find P so we have to make it the subject of the equation.

1 + 0.04 = 1.04
1.04^18 = 2.025816515
Then divide the total amount by this to get 185,110.5454
Therefore the answer is $185,110.55

Hope this helps! :)
4 0
3 years ago
3 cos A = 4 sin A<br>find<br>a) cos A<br>b) 3-cot2 A+ cosec2A<br><br>​
Lady_Fox [76]

Answer:

a). cosA = 4/5

b).

3 - cot {}^{2} a \:  + cosec {}^{2} a \:  = 0

3 0
3 years ago
Read 2 more answers
Sophia earned $294 in 24 hours. How many dollars did she earn per hour?
Vadim26 [7]

Answer:

$12.25

Step-by-step explanation:

Step 1:

$294 : 24        Ratio

Step 2:

$294 ÷ 24     Divide

Answer:

$12.25

Hope This Helps :)

6 0
3 years ago
Read 2 more answers
Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)
DENIUS [597]

Compute the necessary values/derivatives of f(x) at x=1:

f(1)=3

f'(1)=2

f''(1)=-12

f'''(1)=-12

f^{(4)}(1)=48

f^{(5)}(1)=120

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) f(x) at x=1 by

T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5

T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5

###

Another way of doing this would be to solve for the coefficients a,b,c,d,e,g in

f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5

by expanding the right hand side and matching up terms with the same power of x.

5 0
3 years ago
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