Answer:
3.8 seconds
Step-by-step explanation:
Given equation
When the ball hits the ground then height is 0
So we replace h with 0 and solve for t
a= -16 , b= 60 and c= 5
Apply quadratic formula to solve for t
=![\frac{-60+\sqrt{60^2-4\left(-16\right)\cdot \:5}}{2\left(-16\right)}[/tex[tex]=\frac{-60+-\sqrt{3920}}{-32}](https://tex.z-dn.net/?f=%5Cfrac%7B-60%2B%5Csqrt%7B60%5E2-4%5Cleft%28-16%5Cright%29%5Ccdot%20%5C%3A5%7D%7D%7B2%5Cleft%28-16%5Cright%29%7D%5B%2Ftex%3C%2Fp%3E%3Cp%3E%5Btex%5D%3D%5Cfrac%7B-60%2B-%5Csqrt%7B3920%7D%7D%7B-32%7D)
Now make two fractions and solve for x
t= 
=-0.0815
t= 
=3.83
So answer is 3.8 seconds
Answer:
1 inch
Step-by-step explanation:
Factors of 63 are 7 and 9, each of which is 2 more than the dimensions of the photo. Sarah's frame is 1 inch wide.
_____
A 1-inch wide frame adds 2 inches to length and width.
_____
<em>Solution using an equation</em>
If you let w represent the width of the frame, the area of the framed photo is ...
(5+2w)(7+2w) = 63
4w^2 +24w -28 = 0 . . . . write in standard form
w^2 +6w -7 = 0 . . . . . . . . divide by 4
(w -1)(w +7) = 0 . . . . . . . . factor
The positive solution to this equation is w=1.
The width of the frame is 1 inch.
Answer:
i need the slope or i need a picture or another point
Step-by-step explanation:
Minus 1 on both sides
Divide by 3 on both sides
C 5 > 7/3
