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3 years ago

Selecting 2 fully charged batteries in a row from a large batch in which 6 % of the batteries are dead

1 answer:

8 0

The probability of s<span>electing 2 fully charged batteries in a row from a large batch in which 6% of the batteries are dead is given by:

$P(2)=(1-0.06)^2=(0.94)^2=0.8836$ </span>

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Set up an equation that can be used to solve the problem. Solve the equation and determine the desired value.

Nataly [62]

Answer: $454.55

Step-by-step explanation:

Tito's weekly salary is always $ 500 per week.

But your weekly commission income depends on the sales you make. Your commissions are 55%.

If we call x the dollar amount of all sales made by Tito in a week, then his income z(x) is given by the following equation:

$z (x) = 0.55x + 500$

We wish that $z (x) = 750$ .

Then we equate the equation to 750 and solve for the variable x.

$0.55x + 500 = 750\\\\0.55x + 500-500 = 750-500\\\\0.55x = 250$

$\frac{0.55}{0.55}x = \frac{250}{0.55}$

$x = \$\ 454.55$

Total sales made by Tito must be $454.55

7 0

2 years ago

Jenny has saved $3,800 over the last 12 months. She saved either $250 or $350 a month. During the 12 month period, how many time

kari74 [83]

5 months for it 5 times 250= 1250

7 0

3 years ago

Read 2 more answers

What's the answer I'm confused yeahhhhhhhhhh

Fantom [35]

-3 2/5 - 5/6 = -127/30

-2/3 + 6 1/8 = 107/24

3 0

3 years ago

Decrease 700kg by 25% <br> (With working out)

Natali5045456 [20]

Answer: 525kg

Step-by-step explanation:

To decrease 700kg by 25% implies

700 - 25% of 700kg

25% of 700 = 25/100 × 700kg

0.25 x 700

= 175

Therefore, to decrease 700kg by 25%, since 25% is 175kg, we subtract 175kg from 700kg

700kg - 125kg

= 525kg

3 0

3 years ago

Read 2 more answers

The angle of elevation of the top of a pole as seen from a point 13 ft away from the base is double its angle of elevation as se

spayn [35]

The height of the pole above the level of the observer's eyes is 31.42 ft

Let the angle of elevation of the top of the pole from a point 47 ft away be α.

Let the angle of elevation of the top of the pole from the point 13 ft away be β.

Since the angle of elevation of a point 13 feet away is twice that from 47 ft away, we have that β = 2α.

If the height of the pole above the level of the observer's eye is h, we have that

tanβ = tan2α = h/13 and tanα = h/47

From trigonometric identities tan2α = 2tanα/(1 - tan²α)

Substituting the values of the variables into the equation, we have

tan2α = 2tanα/(1 - tan²α)

h/13 = 2h/47 ÷ [1 - (h/47)²]

Dividing through by h, we have

1/13 = 2/47 ÷ [1 - (h/47)²]

Cross-multiplying, we have

1/13 = 2/47 ÷ [1 - (h/47)²]

1 - (h/47)² = 2/47 × 13

1 - (h/47)² = 26/47

(h/47)² = 1 - 26/47

(h/47)² = (47 - 26)/47

(h/47)² = 21/47

Taking square-root of both sides, we have

h/47 = √(21/47)

Cross-multiplyng, we have

h = √(21/47) × 47

h = √(21 × 47)

h = √987

h = 31.42 ft

The height of the pole above the level of the observer's eyes is 31.42 ft

Learn more about height of a pole here:

brainly.com/question/10375496

4 0

2 years ago

Selecting 2 fully charged batteries in a row from a large batch in which 6 ​% of the batteries are dead

Selecting 2 fully charged batteries in a row from a large batch in which 6 % of the batteries are dead