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sukhopar [10]
3 years ago
7

Adjust number into correct standard form, 6552× 10(tex)1 Please answer

Mathematics
1 answer:
Fed [463]3 years ago
7 0

Answer:

6.552×10³×10

6.552×10^3+1

6.552×10^4 is the standard form

i hope this will help you :)

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What is 0.95 in simplest form
solong [7]
0.95 \times \frac{100}{100} = \frac{95}{100} = \frac{19 \times 5}{20\times 5}\\\\ = \boxed{\bf{\frac{19}{20}}}

0.95 in simplest form is 19/20
5 0
3 years ago
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SpyIntel [72]
The correct answer is -2
Can you mark me as brainliest?
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2 years ago
Use the the substitution method to solve the system of linear equations. y = -2x + 6 x=4 enter your answer as an ordered pair
Morgarella [4.7K]

Answer:

The answer would be -2 then.

Step-by-step explanation:

6 0
3 years ago
At a local swimming pool, the diving board is elevated h = 9.5 m above the pool's surface and overhangs the pool edge by L = 2 m
beks73 [17]
<h2>Answer:</h2>

s_{y}=u_{y}t+\frac{1}{2}a_{y}t^{2}\\9.5=4.9t^{2}

and,

v_{x}=1.39a_{x}+2.5

<h2>Step-by-step explanation:</h2>

In the question,

Taking the elevation of pool along the y-axis, and length of the board along the x-axis.

On drawing the illustration in the co-ordinate system we get,

lₓ = 2 m

uₓ = 2.5 m/s

and,

h_{y}=9.5\,m

So,

From the equations of the laws of motion we can state that,

s_{y}=u_{y}t+\frac{1}{2}a_{y}t^{2}

So,

On putting the values we can say that,

s_{y}=u_{y}t+\frac{1}{2}a_{y}t^{2}\\9.5=(0)t+\frac{1}{2}(9.8)t^{2}\\t^{2}=\frac{9.5}{4.9}\\t^{2}=1.93\\t=1.39\,s

Now,

The <u>equation of the motion in the horizontal</u> can be given by,

v_{x}=u_{x}+a_{x}t\\v_{x}=2.5+a_{x}(1.39)\\So,\\v_{x}=1.39a_{x}+2.5

<em><u>Therefore, the equations of the motions in the horizontal and verticals are,</u></em>

s_{y}=u_{y}t+\frac{1}{2}a_{y}t^{2}\\9.5=4.9t^{2}

and,

v_{x}=1.39a_{x}+2.5

6 0
2 years ago
Solve for x. Enter the solutions from least to greatest. (x + 7)^2 - 49 = 0
Marysya12 [62]

Answer:

X will equal 0 , -14

Step-by-step explanation:

You take the root of both sides and solve

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2 years ago
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