Y - y1 = m(x - x1)
slope(m) = 2/5
(-4,-7)....x1 = -4 and y1 = -7....pay attention to ur signs
now we sub
y - (-7) = 2/5(x - (-4)...not done yet
y + 7 = 2/5(x + 4) <===
Answer:
C. T is not one-to-one because the standard matrix A has a free variable.
Step-by-step explanation:
Given
Required
Determine if it is linear or onto
Represent the above as a matrix.
![T(x_1,x_2,x_3) = \left[\begin{array}{ccc}1&-5&4\\0&1&-6\\0&0&0\end{array}\right] \left[\begin{array}{c}x_1&x_2&x_3\end{array}\right]](https://tex.z-dn.net/?f=T%28x_1%2Cx_2%2Cx_3%29%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-5%264%5C%5C0%261%26-6%5C%5C0%260%260%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx_1%26x_2%26x_3%5Cend%7Barray%7D%5Cright%5D)
From the above matrix, we observe that the matrix does not have a pivot in every column.
This means that the column are not linearly independent, & it has a free variable and as such T is not one-on-one
R is also known as the correlation coefficient. Hence your statement is ...
B. False
Answer:
V' = (-1, -4)
Step-by-step explanation:
the original point V (4, -1) is 4 units to the right and 1 unit down.
now we turn this 90° clockwise (upper right to down to upper left).
that means the right part of the x-axis turns into the bottom part of the y-axis, and the bottom part of the y-axis into the left part of the x-axis.
so, positive x turns into negative y, and the negative y turns into negative x.
therefore, (4 -1) turns into (-1, -4).
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